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Aromātai (complex solution)
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Tohaina

5\times \left(3i\right)\sqrt{5}
Tauwehea te -45=\left(3i\right)^{2}\times 5. Tuhia anō te pūtake rua o te hua \sqrt{\left(3i\right)^{2}\times 5} hei hua o ngā pūtake rua \sqrt{\left(3i\right)^{2}}\sqrt{5}. Tuhia te pūtakerua o te \left(3i\right)^{2}.
15i\sqrt{5}
Whakareatia te 5 ki te 3i, ka 15i.