Whakaoti i te 5*20+left(x-5right)4=left(5*20+4xright)09

$$5 \cdot 20+ \left( x-5 \right) 4 = \left( 5 \cdot 20+4x \right) 09$$

Whakaoti mō x

$$x=-20$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakareatia te 5 ki te 20, ka 100.

$$100+\left(x-5\right)\times 4=\left(5\times 20+4x\right)\times 0\times 9$$

Whakamahia te āhuatanga tohatoha hei whakarea te x-5 ki te 4.

$$100+4x-20=\left(5\times 20+4x\right)\times 0\times 9$$

Tangohia te 20 i te 100, ka 80.

$$80+4x=\left(5\times 20+4x\right)\times 0\times 9$$

Whakareatia te 5 ki te 20, ka 100.

$$80+4x=\left(100+4x\right)\times 0\times 9$$

Whakareatia te 0 ki te 9, ka 0.

$$80+4x=\left(100+4x\right)\times 0$$

Ko te tau i whakarea ki te kore ka hua ko te kore.

$$80+4x=0$$

Tangohia te 80 mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$4x=-80$$

Whakawehea ngā taha e rua ki te 4.

$$x=\frac{-80}{4}$$

Whakawehea te -80 ki te 4, kia riro ko -20.

$$x=-20$$