Whakaoti i te 5^2x+1div125=25f

$$5 ^ { 2 x + 1 } \div 125 = 25 f$$

Whakaoti mō f

$$f=\frac{25^{x}}{625}$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakareatia ngā taha e rua o te whārite ki te 125.

$$5^{2x+1}=3125f$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$3125f=5^{2x+1}$$

Whakawehea ngā taha e rua ki te 3125.

$$\frac{3125f}{3125}=\frac{5^{2x+1}}{3125}$$

Mā te whakawehe ki te 3125 ka wetekia te whakareanga ki te 3125.

$$f=\frac{5^{2x+1}}{3125}$$

Whakawehe 5^{1+2x} ki te 3125.

$$f=5^{2x-4}$$

Whakaoti mō x (complex solution)

$$x=\frac{\log_{5}\left(f\right)}{2}+\frac{\pi n_{1}i}{\ln(5)}+2$$

$$n_{1}\in \mathrm{Z}$$

$$f\neq 0$$

Whakaoti mō x

$$x=\frac{\log_{5}\left(f\right)+4}{2}$$

$$f>0$$