Whakaoti i te 5=y^2-8

$$5 = y ^ { 2 } - 8$$

Whakaoti mō y

$$y=\sqrt{13}\approx 3.605551275$$

$$y=-\sqrt{13}\approx -3.605551275$$

Ngā Upane mā te Kimi Pūtakerua

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$y^{2}-8=5$$

Me tāpiri te 8 ki ngā taha e rua.

$$y^{2}=5+8$$

Tāpirihia te 5 ki te 8, ka 13.

$$y^{2}=13$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$y=\sqrt{13} y=-\sqrt{13}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$y^{2}-8=5$$

Tangohia te 5 mai i ngā taha e rua.

$$y^{2}-8-5=0$$

Tangohia te 5 i te -8, ka -13.

$$y^{2}-13=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me -13 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$y=\frac{0±\sqrt{0^{2}-4\left(-13\right)}}{2}$$

Pūrua 0.

$$y=\frac{0±\sqrt{-4\left(-13\right)}}{2}$$

Whakareatia -4 ki te -13.

$$y=\frac{0±\sqrt{52}}{2}$$

Tuhia te pūtakerua o te 52.

$$y=\frac{0±2\sqrt{13}}{2}$$

Nā, me whakaoti te whārite y=\frac{0±2\sqrt{13}}{2} ina he tāpiri te ±.

$$y=\sqrt{13}$$

Nā, me whakaoti te whārite y=\frac{0±2\sqrt{13}}{2} ina he tango te ±.

$$y=-\sqrt{13}$$

Kua oti te whārite te whakatau.

$$y=\sqrt{13} y=-\sqrt{13}$$