Whakaoti i te 48^2+25=x^2

$$48 ^ { 2 } + 25 = x ^ { 2 }$$

Whakaoti mō x

$$x=\sqrt{2329}\approx 48.259714048$$

$$x=-\sqrt{2329}\approx -48.259714048$$

Ngā Upane mā te Kimi Pūtakerua

Tātaihia te 48 mā te pū o 2, kia riro ko 2304.

$$2304+25=x^{2}$$

Tāpirihia te 2304 ki te 25, ka 2329.

$$2329=x^{2}$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$x^{2}=2329$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$x=\sqrt{2329} x=-\sqrt{2329}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Tātaihia te 48 mā te pū o 2, kia riro ko 2304.

$$2304+25=x^{2}$$

Tāpirihia te 2304 ki te 25, ka 2329.

$$2329=x^{2}$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$x^{2}=2329$$

Tangohia te 2329 mai i ngā taha e rua.

$$x^{2}-2329=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me -2329 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-2329\right)}}{2}$$

Pūrua 0.

$$x=\frac{0±\sqrt{-4\left(-2329\right)}}{2}$$

Whakareatia -4 ki te -2329.

$$x=\frac{0±\sqrt{9316}}{2}$$

Tuhia te pūtakerua o te 9316.

$$x=\frac{0±2\sqrt{2329}}{2}$$

Nā, me whakaoti te whārite x=\frac{0±2\sqrt{2329}}{2} ina he tāpiri te ±.

$$x=\sqrt{2329}$$

Nā, me whakaoti te whārite x=\frac{0±2\sqrt{2329}}{2} ina he tango te ±.

$$x=-\sqrt{2329}$$

Kua oti te whārite te whakatau.

$$x=\sqrt{2329} x=-\sqrt{2329}$$