Whakaoti i te 460x^4-5x^2+40x-88

$$460 { x }^{ 4 } -5 { x }^{ 2 } +40x-88$$

Kimi Pārōnaki e ai ki x

$$1840x^{3}-10x+40$$

Ngā Upane e Whakamahi ana i te Ture Pārōnaki mō te Tapeke

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$4\times 460x^{4-1}+2\left(-5\right)x^{2-1}+40x^{1-1}$$

Whakareatia 4 ki te 460.

$$1840x^{4-1}+2\left(-5\right)x^{2-1}+40x^{1-1}$$

Tango 1 mai i 4.

$$1840x^{3}+2\left(-5\right)x^{2-1}+40x^{1-1}$$

Whakareatia 2 ki te -5.

$$1840x^{3}-10x^{2-1}+40x^{1-1}$$

Tango 1 mai i 2.

$$1840x^{3}-10x^{1}+40x^{1-1}$$

Tango 1 mai i 1.

$$1840x^{3}-10x^{1}+40x^{0}$$

Mō tētahi kupu t, t^{1}=t.

$$1840x^{3}-10x+40x^{0}$$

Mō tētahi kupu t mahue te 0, t^{0}=1.

$$1840x^{3}-10x+40\times 1$$

Mō tētahi kupu t, t\times 1=t me 1t=t.

$$1840x^{3}-10x+40$$

Aromātai

$$460x^{4}-5x^{2}+40x-88$$