Whakaoti i te 400=I^250

$$400 = I ^ { 2 } 50$$

Whakaoti mō I

$$I=2\sqrt{2}\approx 2.828427125$$

$$I=-2\sqrt{2}\approx -2.828427125$$

Ngā Upane mā te Kimi Pūtakerua

Whakawehea ngā taha e rua ki te 50.

$$\frac{400}{50}=I^{2}$$

Whakawehea te 400 ki te 50, kia riro ko 8.

$$8=I^{2}$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$I^{2}=8$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$I=2\sqrt{2} I=-2\sqrt{2}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Whakawehea ngā taha e rua ki te 50.

$$\frac{400}{50}=I^{2}$$

Whakawehea te 400 ki te 50, kia riro ko 8.

$$8=I^{2}$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$I^{2}=8$$

Tangohia te 8 mai i ngā taha e rua.

$$I^{2}-8=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me -8 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$I=\frac{0±\sqrt{0^{2}-4\left(-8\right)}}{2}$$

Pūrua 0.

$$I=\frac{0±\sqrt{-4\left(-8\right)}}{2}$$

Whakareatia -4 ki te -8.

$$I=\frac{0±\sqrt{32}}{2}$$

Tuhia te pūtakerua o te 32.

$$I=\frac{0±4\sqrt{2}}{2}$$

Nā, me whakaoti te whārite I=\frac{0±4\sqrt{2}}{2} ina he tāpiri te ±.

$$I=2\sqrt{2}$$

Nā, me whakaoti te whārite I=\frac{0±4\sqrt{2}}{2} ina he tango te ±.

$$I=-2\sqrt{2}$$

Kua oti te whārite te whakatau.

$$I=2\sqrt{2} I=-2\sqrt{2}$$