Whakaoti i te 40x-[20-(5-2x)]=3-(-8x-12)

$$40 x - [ 20 - ( 5 - 2 x ) ] = 3 - ( - 8 x - 12 )$$

Whakaoti mō x

$$x=1$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Hei kimi i te tauaro o 5-2x, kimihia te tauaro o ia taurangi.

$$40x-\left(20-5-\left(-2x\right)\right)=3-\left(-8x-12\right)$$

Ko te tauaro o -2x ko 2x.

$$40x-\left(20-5+2x\right)=3-\left(-8x-12\right)$$

Tangohia te 5 i te 20, ka 15.

$$40x-\left(15+2x\right)=3-\left(-8x-12\right)$$

Hei kimi i te tauaro o 15+2x, kimihia te tauaro o ia taurangi.

$$40x-15-2x=3-\left(-8x-12\right)$$

Pahekotia te 40x me -2x, ka 38x.

$$38x-15=3-\left(-8x-12\right)$$

Hei kimi i te tauaro o -8x-12, kimihia te tauaro o ia taurangi.

$$38x-15=3-\left(-8x\right)-\left(-12\right)$$

Ko te tauaro o -8x ko 8x.

$$38x-15=3+8x-\left(-12\right)$$

Ko te tauaro o -12 ko 12.

$$38x-15=3+8x+12$$

Tāpirihia te 3 ki te 12, ka 15.

$$38x-15=15+8x$$

Tangohia te 8x mai i ngā taha e rua.

$$38x-15-8x=15$$

Pahekotia te 38x me -8x, ka 30x.

$$30x-15=15$$

Me tāpiri te 15 ki ngā taha e rua.

$$30x=15+15$$

Tāpirihia te 15 ki te 15, ka 30.

$$30x=30$$

Whakawehea ngā taha e rua ki te 30.

$$x=\frac{30}{30}$$

Whakawehea te 30 ki te 30, kia riro ko 1.

$$x=1$$