Whakaoti i te 40sqrt{6}*frac{sqrt{6}+sqrt{2}}{4}

$$40 \sqrt { 6 } \times \frac { \sqrt { 6 } + \sqrt { 2 } } { 4 }$$

Aromātai

$$20\sqrt{3}+60\approx 94.641016151$$

Ngā Upane Otinga

Whakakorea atu te tauwehe pūnoa nui rawa 4 i roto i te 40 me te 4.

$$10\left(\sqrt{6}+\sqrt{2}\right)\sqrt{6}$$

Whakamahia te āhuatanga tohatoha hei whakarea te 10 ki te \sqrt{6}+\sqrt{2}.

$$\left(10\sqrt{6}+10\sqrt{2}\right)\sqrt{6}$$

Whakamahia te āhuatanga tohatoha hei whakarea te 10\sqrt{6}+10\sqrt{2} ki te \sqrt{6}.

$$10\left(\sqrt{6}\right)^{2}+10\sqrt{2}\sqrt{6}$$

Ko te pūrua o \sqrt{6} ko 6.

$$10\times 6+10\sqrt{2}\sqrt{6}$$

Whakareatia te 10 ki te 6, ka 60.

$$60+10\sqrt{2}\sqrt{6}$$

Tauwehea te 6=2\times 3. Tuhia anō te pūtake rua o te hua \sqrt{2\times 3} hei hua o ngā pūtake rua \sqrt{2}\sqrt{3}.

$$60+10\sqrt{2}\sqrt{2}\sqrt{3}$$

Whakareatia te \sqrt{2} ki te \sqrt{2}, ka 2.

$$60+10\times 2\sqrt{3}$$

Whakareatia te 10 ki te 2, ka 20.

$$60+20\sqrt{3}$$