Whakaoti i te 4-2x+6x^2

$$4-2x+6 { x }^{ 2 }$$

Tauwehe

$$2\left(3x^{2}-x+2\right)$$

Ngā Upane Otinga

Tauwehea te 2. Kāore te pūrau 2-x+3x^{2} i whakatauwehea i te mea kāhore ōna pūtake whakahau.

$$2\left(2-x+3x^{2}\right)$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Ka taea te huamaha pūrua te tauwehe mā te whakamahi i te huringa ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), ina ko x_{1} me x_{2} ngā otinga o te whārite pūrua ax^{2}+bx+c=0.

$$6x^{2}-2x+4=0$$

Ko ngā whārite katoa o te āhua ax^{2}+bx+c=0 ka taea te whakaoti mā te whakamahi i te tikanga tātai pūrua: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. E rua ngā otinga ka puta i te tikanga tātai pūrua, ko tētahi ina he tāpiri a ±, ā, ko tētahi ina he tango.

$$x=\frac{-\left(-2\right)±\sqrt{\left(-2\right)^{2}-4\times 6\times 4}}{2\times 6}$$

Pūrua -2.

$$x=\frac{-\left(-2\right)±\sqrt{4-4\times 6\times 4}}{2\times 6}$$

Whakareatia -4 ki te 6.

$$x=\frac{-\left(-2\right)±\sqrt{4-24\times 4}}{2\times 6}$$

Whakareatia -24 ki te 4.

$$x=\frac{-\left(-2\right)±\sqrt{4-96}}{2\times 6}$$

Tāpiri 4 ki te -96.

$$x=\frac{-\left(-2\right)±\sqrt{-92}}{2\times 6}$$

Tā te mea e kore te pūrua o tētahi tau tōraro e tautohutia ki te āpure tūturu, kāhore he rongoā. Kāore e taea te pūrau pūrua te whakatauwehe.

$$6x^{2}-2x+4$$

Aromātai

$$6x^{2}-2x+4$$