Whakaoti i te 4-2/3(x-1)=x-2

$$4- \frac{ 2 }{ 3 } (x-1)=x-2$$

Whakaoti mō x

$$x=4$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te -\frac{2}{3} ki te x-1.

$$4-\frac{2}{3}x-\frac{2}{3}\left(-1\right)=x-2$$

Whakareatia te -\frac{2}{3} ki te -1, ka \frac{2}{3}.

$$4-\frac{2}{3}x+\frac{2}{3}=x-2$$

Me tahuri te 4 ki te hautau \frac{12}{3}.

$$\frac{12}{3}-\frac{2}{3}x+\frac{2}{3}=x-2$$

Tā te mea he rite te tauraro o \frac{12}{3} me \frac{2}{3}, me tāpiri rāua mā te tāpiri i ō raua taurunga.

$$\frac{12+2}{3}-\frac{2}{3}x=x-2$$

Tāpirihia te 12 ki te 2, ka 14.

$$\frac{14}{3}-\frac{2}{3}x=x-2$$

Tangohia te x mai i ngā taha e rua.

$$\frac{14}{3}-\frac{2}{3}x-x=-2$$

Pahekotia te -\frac{2}{3}x me -x, ka -\frac{5}{3}x.

$$\frac{14}{3}-\frac{5}{3}x=-2$$

Tangohia te \frac{14}{3} mai i ngā taha e rua.

$$-\frac{5}{3}x=-2-\frac{14}{3}$$

Me tahuri te -2 ki te hautau -\frac{6}{3}.

$$-\frac{5}{3}x=-\frac{6}{3}-\frac{14}{3}$$

Tā te mea he rite te tauraro o -\frac{6}{3} me \frac{14}{3}, me tango rāua mā te tango i ō raua taurunga.

$$-\frac{5}{3}x=\frac{-6-14}{3}$$

Tangohia te 14 i te -6, ka -20.

$$-\frac{5}{3}x=-\frac{20}{3}$$

Me whakarea ngā taha e rua ki te -\frac{3}{5}, te tau utu o -\frac{5}{3}.

$$x=-\frac{20}{3}\left(-\frac{3}{5}\right)$$

Me whakarea te -\frac{20}{3} ki te -\frac{3}{5} mā te whakarea taurunga ki te taurunga me te tauraro ki te tauraro.

$$x=\frac{-20\left(-3\right)}{3\times 5}$$

Mahia ngā whakarea i roto i te hautanga \frac{-20\left(-3\right)}{3\times 5}.

$$x=\frac{60}{15}$$

Whakawehea te 60 ki te 15, kia riro ko 4.

$$x=4$$