Whakaoti i te 4+2sqrt{3}+2sqrt{3}+3=x+bsqrt{3}

$$4+2 \sqrt{ 3 } +2 \sqrt{ 3 } +3 = x+b \sqrt{ 3 }$$

Whakaoti mō b

$$b=-\frac{\sqrt{3}\left(x-4\sqrt{3}-7\right)}{3}$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Pahekotia te 2\sqrt{3} me 2\sqrt{3}, ka 4\sqrt{3}.

$$4+4\sqrt{3}+3=x+b\sqrt{3}$$

Tāpirihia te 4 ki te 3, ka 7.

$$7+4\sqrt{3}=x+b\sqrt{3}$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$x+b\sqrt{3}=7+4\sqrt{3}$$

Tangohia te x mai i ngā taha e rua.

$$b\sqrt{3}=7+4\sqrt{3}-x$$

He hanga arowhānui tō te whārite.

$$\sqrt{3}b=-x+4\sqrt{3}+7$$

Whakawehea ngā taha e rua ki te \sqrt{3}.

$$\frac{\sqrt{3}b}{\sqrt{3}}=\frac{-x+4\sqrt{3}+7}{\sqrt{3}}$$

Mā te whakawehe ki te \sqrt{3} ka wetekia te whakareanga ki te \sqrt{3}.

$$b=\frac{-x+4\sqrt{3}+7}{\sqrt{3}}$$

Whakawehe 7+4\sqrt{3}-x ki te \sqrt{3}.

$$b=\frac{\sqrt{3}\left(-x+4\sqrt{3}+7\right)}{3}$$

Whakaoti mō x

$$x=\sqrt{3}\left(4-b\right)+7$$