Whakaoti i te 4+x^2=16+left(4-xright)^2

$$4+ { x }^{ 2 } =16+ { \left(4-x \right) }^{ 2 }$$

Whakaoti mō x

$$x = \frac{7}{2} = 3\frac{1}{2} = 3.5$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te ture huarua \left(a-b\right)^{2}=a^{2}-2ab+b^{2} hei whakaroha \left(4-x\right)^{2}.

$$4+x^{2}=16+16-8x+x^{2}$$

Tāpirihia te 16 ki te 16, ka 32.

$$4+x^{2}=32-8x+x^{2}$$

Me tāpiri te 8x ki ngā taha e rua.

$$4+x^{2}+8x=32+x^{2}$$

Tangohia te x^{2} mai i ngā taha e rua.

$$4+x^{2}+8x-x^{2}=32$$

Pahekotia te x^{2} me -x^{2}, ka 0.

$$4+8x=32$$

Tangohia te 4 mai i ngā taha e rua.

$$8x=32-4$$

Tangohia te 4 i te 32, ka 28.

$$8x=28$$

Whakawehea ngā taha e rua ki te 8.

$$x=\frac{28}{8}$$

Whakahekea te hautanga \frac{28}{8} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 4.

$$x=\frac{7}{2}$$