Whakaoti i te 4x-2x^2

$$4 x - 2 x ^ { 2 }$$

Tauwehe

$$2x\left(2-x\right)$$

Ngā Upane Otinga

Tauwehea te 2.

$$2\left(2x-x^{2}\right)$$

Whakaarohia te 2x-x^{2}. Tauwehea te x.

$$x\left(2-x\right)$$

Me tuhi anō te kīanga whakatauwehe katoa.

$$2x\left(-x+2\right)$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Ka taea te huamaha pūrua te tauwehe mā te whakamahi i te huringa ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), ina ko x_{1} me x_{2} ngā otinga o te whārite pūrua ax^{2}+bx+c=0.

$$-2x^{2}+4x=0$$

Ko ngā whārite katoa o te āhua ax^{2}+bx+c=0 ka taea te whakaoti mā te whakamahi i te tikanga tātai pūrua: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. E rua ngā otinga ka puta i te tikanga tātai pūrua, ko tētahi ina he tāpiri a ±, ā, ko tētahi ina he tango.

$$x=\frac{-4±\sqrt{4^{2}}}{2\left(-2\right)}$$

Tuhia te pūtakerua o te 4^{2}.

$$x=\frac{-4±4}{2\left(-2\right)}$$

Whakareatia 2 ki te -2.

$$x=\frac{-4±4}{-4}$$

Nā, me whakaoti te whārite x=\frac{-4±4}{-4} ina he tāpiri te ±. Tāpiri -4 ki te 4.

$$x=\frac{0}{-4}$$

Whakawehe 0 ki te -4.

$$x=0$$

Nā, me whakaoti te whārite x=\frac{-4±4}{-4} ina he tango te ±. Tango 4 mai i -4.

$$x=-\frac{8}{-4}$$

Whakawehe -8 ki te -4.

$$x=2$$

Tauwehea te kīanga taketake mā te whakamahi i te ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Me whakakapi te 0 mō te x_{1} me te 2 mō te x_{2}.

$$-2x^{2}+4x=-2x\left(x-2\right)$$

Aromātai

$$2x\left(2-x\right)$$