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\left(2x-5\right)\left(2x+5\right)=0
Whakaarohia te 4x^{2}-25. Tuhia anō te 4x^{2}-25 hei \left(2x\right)^{2}-5^{2}. Ka taea te rerekētanga o ngā pūrua te whakatauwehe mā te ture: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).
x=\frac{5}{2} x=-\frac{5}{2}
Hei kimi otinga whārite, me whakaoti te 2x-5=0 me te 2x+5=0.
4x^{2}=25
Me tāpiri te 25 ki ngā taha e rua. Ko te tau i tāpiria he kore ka hua koia tonu.
x^{2}=\frac{25}{4}
Whakawehea ngā taha e rua ki te 4.
x=\frac{5}{2} x=-\frac{5}{2}
Tuhia te pūtakerua o ngā taha e rua o te whārite.
4x^{2}-25=0
Ko ngā tikanga tātai pūrua pēnei i tēnei nā, me te kīanga tau x^{2} engari kāore he kīanga tau x, ka taea tonu te whakaoti mā te whakamahi i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, ina tuhia ki te tānga ngahuru: ax^{2}+bx+c=0.
x=\frac{0±\sqrt{0^{2}-4\times 4\left(-25\right)}}{2\times 4}
Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 4 mō a, 0 mō b, me -25 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\times 4\left(-25\right)}}{2\times 4}
Pūrua 0.
x=\frac{0±\sqrt{-16\left(-25\right)}}{2\times 4}
Whakareatia -4 ki te 4.
x=\frac{0±\sqrt{400}}{2\times 4}
Whakareatia -16 ki te -25.
x=\frac{0±20}{2\times 4}
Tuhia te pūtakerua o te 400.
x=\frac{0±20}{8}
Whakareatia 2 ki te 4.
x=\frac{5}{2}
Nā, me whakaoti te whārite x=\frac{0±20}{8} ina he tāpiri te ±. Whakahekea te hautanga \frac{20}{8} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 4.
x=-\frac{5}{2}
Nā, me whakaoti te whārite x=\frac{0±20}{8} ina he tango te ±. Whakahekea te hautanga \frac{-20}{8} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 4.
x=\frac{5}{2} x=-\frac{5}{2}
Kua oti te whārite te whakatau.