Whakaoti i te 4x^2+7x+33=0

$$4 x ^ { 2 } + 7 x + 33 = 0$$

Whakaoti mō x (complex solution)

$$x=\frac{-7+\sqrt{479}i}{8}\approx -0.875+2.735758579i$$

$$x=\frac{-\sqrt{479}i-7}{8}\approx -0.875-2.735758579i$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Ko ngā whārite katoa o te āhua ax^{2}+bx+c=0 ka taea te whakaoti mā te whakamahi i te tikanga tātai pūrua: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. E rua ngā otinga ka puta i te tikanga tātai pūrua, ko tētahi ina he tāpiri a ±, ā, ko tētahi ina he tango.

$$4x^{2}+7x+33=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 4 mō a, 7 mō b, me 33 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{-7±\sqrt{7^{2}-4\times 4\times 33}}{2\times 4}$$

Pūrua 7.

$$x=\frac{-7±\sqrt{49-4\times 4\times 33}}{2\times 4}$$

Whakareatia -4 ki te 4.

$$x=\frac{-7±\sqrt{49-16\times 33}}{2\times 4}$$

Whakareatia -16 ki te 33.

$$x=\frac{-7±\sqrt{49-528}}{2\times 4}$$

Tāpiri 49 ki te -528.

$$x=\frac{-7±\sqrt{-479}}{2\times 4}$$

Tuhia te pūtakerua o te -479.

$$x=\frac{-7±\sqrt{479}i}{2\times 4}$$

Whakareatia 2 ki te 4.

$$x=\frac{-7±\sqrt{479}i}{8}$$

Nā, me whakaoti te whārite x=\frac{-7±\sqrt{479}i}{8} ina he tāpiri te ±. Tāpiri -7 ki te i\sqrt{479}.

$$x=\frac{-7+\sqrt{479}i}{8}$$

Nā, me whakaoti te whārite x=\frac{-7±\sqrt{479}i}{8} ina he tango te ±. Tango i\sqrt{479} mai i -7.

$$x=\frac{-\sqrt{479}i-7}{8}$$

Kua oti te whārite te whakatau.

$$x=\frac{-7+\sqrt{479}i}{8} x=\frac{-\sqrt{479}i-7}{8}$$

Ngā Upane mō te Whakaoti i te Pūrua

Ko ngā whārite pūrua pēnei i tēnei nā ka taea te whakaoti mā te whakaoti i te pūrua. Hei whakaoti i te pūrua, ko te whārite me mātua tuhi ki te āhua x^{2}+bx=c.

$$4x^{2}+7x+33=0$$

Me tango 33 mai i ngā taha e rua o te whārite.

$$4x^{2}+7x+33-33=-33$$

Mā te tango i te 33 i a ia ake anō ka toe ko te 0.

$$4x^{2}+7x=-33$$

Whakawehea ngā taha e rua ki te 4.

$$\frac{4x^{2}+7x}{4}=-\frac{33}{4}$$

Mā te whakawehe ki te 4 ka wetekia te whakareanga ki te 4.

$$x^{2}+\frac{7}{4}x=-\frac{33}{4}$$

Whakawehea te \frac{7}{4}, te tau whakarea o te kīanga tau x, ki te 2 kia riro ai te \frac{7}{8}. Nā, tāpiria te pūrua o te \frac{7}{8} ki ngā taha e rua o te whārite. Mā konei e pūrua tika tonu ai te taha mauī o te whārite.

$$x^{2}+\frac{7}{4}x+\left(\frac{7}{8}\right)^{2}=-\frac{33}{4}+\left(\frac{7}{8}\right)^{2}$$

Pūruatia \frac{7}{8} mā te pūrua i te taurunga me te tauraro o te hautanga.

$$x^{2}+\frac{7}{4}x+\frac{49}{64}=-\frac{33}{4}+\frac{49}{64}$$

Tāpiri -\frac{33}{4} ki te \frac{49}{64} mā te kimi i te tauraro pātahi me te tāpiri i ngā taurunga. Ka whakaiti i te hautanga ki ngā kīanga tau iti rawa e taea ana.

$$x^{2}+\frac{7}{4}x+\frac{49}{64}=-\frac{479}{64}$$

Tauwehea x^{2}+\frac{7}{4}x+\frac{49}{64}. Ko te tikanga pūnoa, ina ko x^{2}+bx+c he pūrua tika pūrua tika pū, ka taea taua mea te tauwehea i ngā wā katoa hei \left(x+\frac{b}{2}\right)^{2}.

$$\left(x+\frac{7}{8}\right)^{2}=-\frac{479}{64}$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$\sqrt{\left(x+\frac{7}{8}\right)^{2}}=\sqrt{-\frac{479}{64}}$$

Whakarūnātia.

$$x+\frac{7}{8}=\frac{\sqrt{479}i}{8} x+\frac{7}{8}=-\frac{\sqrt{479}i}{8}$$

Me tango \frac{7}{8} mai i ngā taha e rua o te whārite.

$$x=\frac{-7+\sqrt{479}i}{8} x=\frac{-\sqrt{479}i-7}{8}$$