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\left(4x\right)^{2}=\left(\sqrt{12x-2}\right)^{2}
Pūruatia ngā taha e rua o te whārite.
4^{2}x^{2}=\left(\sqrt{12x-2}\right)^{2}
Whakarohaina te \left(4x\right)^{2}.
16x^{2}=\left(\sqrt{12x-2}\right)^{2}
Tātaihia te 4 mā te pū o 2, kia riro ko 16.
16x^{2}=12x-2
Tātaihia te \sqrt{12x-2} mā te pū o 2, kia riro ko 12x-2.
16x^{2}-12x=-2
Tangohia te 12x mai i ngā taha e rua.
16x^{2}-12x+2=0
Me tāpiri te 2 ki ngā taha e rua.
8x^{2}-6x+1=0
Whakawehea ngā taha e rua ki te 2.
a+b=-6 ab=8\times 1=8
Hei whakaoti i te whārite, whakatauwehea te taha mauī mā te whakarōpū. Tuatahi, me tuhi anō te taha mauī hei 8x^{2}+ax+bx+1. Hei kimi a me b, whakaritea tētahi pūnaha kia whakaoti.
-1,-8 -2,-4
I te mea kua tōrunga te ab, he ōrite te tohu o a me b. I te mea kua tōraro te a+b, he tōraro hoki a a me b. Whakarārangitia ngā tau tōpū takirua pērā katoa ka hoatu i te hua 8.
-1-8=-9 -2-4=-6
Tātaihia te tapeke mō ia takirua.
a=-4 b=-2
Ko te otinga te takirua ka hoatu i te tapeke -6.
\left(8x^{2}-4x\right)+\left(-2x+1\right)
Tuhia anō te 8x^{2}-6x+1 hei \left(8x^{2}-4x\right)+\left(-2x+1\right).
4x\left(2x-1\right)-\left(2x-1\right)
Tauwehea te 4x i te tuatahi me te -1 i te rōpū tuarua.
\left(2x-1\right)\left(4x-1\right)
Whakatauwehea atu te kīanga pātahi 2x-1 mā te whakamahi i te āhuatanga tātai tohatoha.
x=\frac{1}{2} x=\frac{1}{4}
Hei kimi otinga whārite, me whakaoti te 2x-1=0 me te 4x-1=0.
4\times \frac{1}{2}=\sqrt{12\times \frac{1}{2}-2}
Whakakapia te \frac{1}{2} mō te x i te whārite 4x=\sqrt{12x-2}.
2=2
Whakarūnātia. Ko te uara x=\frac{1}{2} kua ngata te whārite.
4\times \frac{1}{4}=\sqrt{12\times \frac{1}{4}-2}
Whakakapia te \frac{1}{4} mō te x i te whārite 4x=\sqrt{12x-2}.
1=1
Whakarūnātia. Ko te uara x=\frac{1}{4} kua ngata te whārite.
x=\frac{1}{2} x=\frac{1}{4}
Rārangihia ngā rongoā katoa o 4x=\sqrt{12x-2}.