Whakaoti i te 4x+13-9x+1x^2+7x+1x^2

$$4 x + 13 - 9 x + 1 x ^ { 2 } + 7 x + 1 x ^ { 2 }$$

Aromātai

$$2x^{2}+2x+13$$

Ngā Upane Otinga

Pahekotia te 4x me -9x, ka -5x.

$$-5x+13+1x^{2}+7x+1x^{2}$$

Pahekotia te -5x me 7x, ka 2x.

$$2x+13+1x^{2}+1x^{2}$$

Pahekotia te 1x^{2} me 1x^{2}, ka 2x^{2}.

$$2x+13+2x^{2}$$

Kimi Pārōnaki e ai ki x

$$4x+2$$

Ngā Upane e Whakamahi ana i te Ture Pārōnaki mō te Tapeke

Pahekotia te 4x me -9x, ka -5x.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-5x+13+1x^{2}+7x+1x^{2})$$

Pahekotia te -5x me 7x, ka 2x.

$$\frac{\mathrm{d}}{\mathrm{d}x}(2x+13+1x^{2}+1x^{2})$$

Pahekotia te 1x^{2} me 1x^{2}, ka 2x^{2}.

$$\frac{\mathrm{d}}{\mathrm{d}x}(2x+13+2x^{2})$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$2x^{1-1}+2\times 2x^{2-1}$$

Tango 1 mai i 1.

$$2x^{0}+2\times 2x^{2-1}$$

Whakareatia 2 ki te 2.

$$2x^{0}+4x^{2-1}$$

Tango 1 mai i 2.

$$2x^{0}+4x^{1}$$

Mō tētahi kupu t, t^{1}=t.

$$2x^{0}+4x$$

Mō tētahi kupu t mahue te 0, t^{0}=1.

$$2\times 1+4x$$

Mō tētahi kupu t, t\times 1=t me 1t=t.

$$2+4x$$