Whakaoti i te 4u^2+8u

$$4 u ^ { 2 } + 8 u$$

Tauwehe

$$4u\left(u+2\right)$$

Ngā Upane Otinga

Tauwehea te 4.

$$4\left(u^{2}+2u\right)$$

Whakaarohia te u^{2}+2u. Tauwehea te u.

$$u\left(u+2\right)$$

Me tuhi anō te kīanga whakatauwehe katoa.

$$4u\left(u+2\right)$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Ka taea te huamaha pūrua te tauwehe mā te whakamahi i te huringa ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), ina ko x_{1} me x_{2} ngā otinga o te whārite pūrua ax^{2}+bx+c=0.

$$4u^{2}+8u=0$$

Ko ngā whārite katoa o te āhua ax^{2}+bx+c=0 ka taea te whakaoti mā te whakamahi i te tikanga tātai pūrua: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. E rua ngā otinga ka puta i te tikanga tātai pūrua, ko tētahi ina he tāpiri a ±, ā, ko tētahi ina he tango.

$$u=\frac{-8±\sqrt{8^{2}}}{2\times 4}$$

Tuhia te pūtakerua o te 8^{2}.

$$u=\frac{-8±8}{2\times 4}$$

Whakareatia 2 ki te 4.

$$u=\frac{-8±8}{8}$$

Nā, me whakaoti te whārite u=\frac{-8±8}{8} ina he tāpiri te ±. Tāpiri -8 ki te 8.

$$u=\frac{0}{8}$$

Whakawehe 0 ki te 8.

$$u=0$$

Nā, me whakaoti te whārite u=\frac{-8±8}{8} ina he tango te ±. Tango 8 mai i -8.

$$u=-\frac{16}{8}$$

Whakawehe -16 ki te 8.

$$u=-2$$

Tauwehea te kīanga taketake mā te whakamahi i te ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Me whakakapi te 0 mō te x_{1} me te -2 mō te x_{2}.

$$4u^{2}+8u=4u\left(u-\left(-2\right)\right)$$

Whakamāmātia ngā kīanga katoa o te āhua p-\left(-q\right) ki te p+q.

$$4u^{2}+8u=4u\left(u+2\right)$$

Aromātai

$$4u\left(u+2\right)$$