Whakaoti i te 4a^2+2b+2c=0

$$4 a ^ { 2 } + 2 b + 2 c = 0$$

Whakaoti mō b

$$b=-\left(2a^{2}+c\right)$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tangohia te 4a^{2} mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$2b+2c=-4a^{2}$$

Tangohia te 2c mai i ngā taha e rua.

$$2b=-4a^{2}-2c$$

Whakawehea ngā taha e rua ki te 2.

$$\frac{2b}{2}=\frac{-4a^{2}-2c}{2}$$

Mā te whakawehe ki te 2 ka wetekia te whakareanga ki te 2.

$$b=\frac{-4a^{2}-2c}{2}$$

Whakawehe -4a^{2}-2c ki te 2.

$$b=-2a^{2}-c$$

Whakaoti mō a

$$a=\frac{\sqrt{-2b-2c}}{2}$$

$$a=-\frac{\sqrt{-2b-2c}}{2}\text{, }b\leq -c$$