Whakaoti i te 4-(1-2x)-(2x+1)=10-2(4+x)

$$4 - ( 1 - 2 x ) - ( 2 x + 1 ) = 10 - 2 ( 4 + x )$$

Whakaoti mō x

$$x=0$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Hei kimi i te tauaro o 1-2x, kimihia te tauaro o ia taurangi.

$$4-1-\left(-2x\right)-\left(2x+1\right)=10-2\left(4+x\right)$$

Ko te tauaro o -2x ko 2x.

$$4-1+2x-\left(2x+1\right)=10-2\left(4+x\right)$$

Tangohia te 1 i te 4, ka 3.

$$3+2x-\left(2x+1\right)=10-2\left(4+x\right)$$

Hei kimi i te tauaro o 2x+1, kimihia te tauaro o ia taurangi.

$$3+2x-2x-1=10-2\left(4+x\right)$$

Pahekotia te 2x me -2x, ka 0.

$$3-1=10-2\left(4+x\right)$$

Tangohia te 1 i te 3, ka 2.

$$2=10-2\left(4+x\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te -2 ki te 4+x.

$$2=10-8-2x$$

Tangohia te 8 i te 10, ka 2.

$$2=2-2x$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$2-2x=2$$

Tangohia te 2 mai i ngā taha e rua.

$$-2x=2-2$$

Tangohia te 2 i te 2, ka 0.

$$-2x=0$$

He ōrite te hua o ngā tau e rua ki 0 ina 0 tētahi o rāua te iti rawa. Tātemea kāore te -2 e ōrite ki 0, me ōrite pū te x ki 0.

$$x=0$$