Whakaoti i te 4(x+2)-5(x+3)<8x+6

$$4 ( x + 2 ) - 5 ( x + 3 ) < 8 x + 6$$

Whakaoti mō x

$$x>-\frac{13}{9}$$

Ngā Upane Otinga

Whakamahia te āhuatanga tohatoha hei whakarea te 4 ki te x+2.

$$4x+8-5\left(x+3\right)<8x+6$$

Whakamahia te āhuatanga tohatoha hei whakarea te -5 ki te x+3.

$$4x+8-5x-15<8x+6$$

Pahekotia te 4x me -5x, ka -x.

$$-x+8-15<8x+6$$

Tangohia te 15 i te 8, ka -7.

$$-x-7<8x+6$$

Tangohia te 8x mai i ngā taha e rua.

$$-x-7-8x<6$$

Pahekotia te -x me -8x, ka -9x.

$$-9x-7<6$$

Me tāpiri te 7 ki ngā taha e rua.

$$-9x<6+7$$

Tāpirihia te 6 ki te 7, ka 13.

$$-9x<13$$

Whakawehea ngā taha e rua ki te -9. I te mea he tōraro a -9, ka huri te ahunga koreōrite.

$$x>-\frac{13}{9}$$