Whakaoti i te 4(8-5x)^2-49=-24

$$4 ( 8 - 5 x ) ^ { 2 } - 49 = - 24$$

Whakaoti mō x

$$x = \frac{11}{10} = 1\frac{1}{10} = 1.1$$

$$x = \frac{21}{10} = 2\frac{1}{10} = 2.1$$

Ngā Upane mā te Kimi Pūtakerua

Me tāpiri 49 ki ngā taha e rua o te whārite.

$$4\left(-5x+8\right)^{2}-49+49=-24+49$$

Mā te tango i te 49 i a ia ake anō ka toe ko te 0.

$$4\left(-5x+8\right)^{2}=-24+49$$

Tāpiri -24 ki te 49.

$$4\left(-5x+8\right)^{2}=25$$

Whakawehea ngā taha e rua ki te 4.

$$\frac{4\left(-5x+8\right)^{2}}{4}=\frac{25}{4}$$

Mā te whakawehe ki te 4 ka wetekia te whakareanga ki te 4.

$$\left(-5x+8\right)^{2}=\frac{25}{4}$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$-5x+8=\frac{5}{2} -5x+8=-\frac{5}{2}$$

Me tango 8 mai i ngā taha e rua o te whārite.

$$-5x+8-8=\frac{5}{2}-8 -5x+8-8=-\frac{5}{2}-8$$

Mā te tango i te 8 i a ia ake anō ka toe ko te 0.

$$-5x=\frac{5}{2}-8 -5x=-\frac{5}{2}-8$$

Tango 8 mai i \frac{5}{2}.

$$-5x=-\frac{11}{2}$$

Tango 8 mai i -\frac{5}{2}.

$$-5x=-\frac{21}{2}$$

Whakawehea ngā taha e rua ki te -5.

$$\frac{-5x}{-5}=-\frac{\frac{11}{2}}{-5} \frac{-5x}{-5}=-\frac{\frac{21}{2}}{-5}$$

Mā te whakawehe ki te -5 ka wetekia te whakareanga ki te -5.

$$x=-\frac{\frac{11}{2}}{-5} x=-\frac{\frac{21}{2}}{-5}$$

Whakawehe -\frac{11}{2} ki te -5.

$$x=\frac{11}{10}$$

Whakawehe -\frac{21}{2} ki te -5.

$$x=\frac{21}{10}$$

Kua oti te whārite te whakatau.

$$x=\frac{11}{10} x=\frac{21}{10}$$