Whakaoti i te 4sqrt{a}=sqrt{4a+27}

$$4 \sqrt{ a } = \sqrt{ 4a+27 }$$

Whakaoti mō a

$$a = \frac{9}{4} = 2\frac{1}{4} = 2.25$$

Ngā Upane Otinga

Pūruatia ngā taha e rua o te whārite.

$$\left(4\sqrt{a}\right)^{2}=\left(\sqrt{4a+27}\right)^{2}$$

Whakarohaina te \left(4\sqrt{a}\right)^{2}.

$$4^{2}\left(\sqrt{a}\right)^{2}=\left(\sqrt{4a+27}\right)^{2}$$

Tātaihia te 4 mā te pū o 2, kia riro ko 16.

$$16\left(\sqrt{a}\right)^{2}=\left(\sqrt{4a+27}\right)^{2}$$

Tātaihia te \sqrt{a} mā te pū o 2, kia riro ko a.

$$16a=\left(\sqrt{4a+27}\right)^{2}$$

Tātaihia te \sqrt{4a+27} mā te pū o 2, kia riro ko 4a+27.

$$16a=4a+27$$

Tangohia te 4a mai i ngā taha e rua.

$$16a-4a=27$$

Pahekotia te 16a me -4a, ka 12a.

$$12a=27$$

Whakawehea ngā taha e rua ki te 12.

$$a=\frac{27}{12}$$

Whakahekea te hautanga \frac{27}{12} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 3.

$$a=\frac{9}{4}$$

Whakakapia te \frac{9}{4} mō te a i te whārite 4\sqrt{a}=\sqrt{4a+27}.

$$4\sqrt{\frac{9}{4}}=\sqrt{4\times \frac{9}{4}+27}$$

Whakarūnātia. Ko te uara a=\frac{9}{4} kua ngata te whārite.

$$6=6$$

Ko te whārite 4\sqrt{a}=\sqrt{4a+27} he rongoā ahurei.

$$a=\frac{9}{4}$$