Whakaoti i te 4=sqrt{26-5x+x}

$$4 = \sqrt { 26 - 5 x + x }$$

Whakaoti mō x

$$x = \frac{5}{2} = 2\frac{1}{2} = 2.5$$

Ngā Upane mō te Whakaoti Whārite Pūtake

Pahekotia te -5x me x, ka -4x.

$$4=\sqrt{26-4x}$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$\sqrt{26-4x}=4$$

Pūruatia ngā taha e rua o te whārite.

$$-4x+26=16$$

Me tango 26 mai i ngā taha e rua o te whārite.

$$-4x+26-26=16-26$$

Mā te tango i te 26 i a ia ake anō ka toe ko te 0.

$$-4x=16-26$$

Tango 26 mai i 16.

$$-4x=-10$$

Whakawehea ngā taha e rua ki te -4.

$$\frac{-4x}{-4}=-\frac{10}{-4}$$

Mā te whakawehe ki te -4 ka wetekia te whakareanga ki te -4.

$$x=-\frac{10}{-4}$$

Whakahekea te hautanga \frac{-10}{-4} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 2.

$$x=\frac{5}{2}$$