Whakaoti i te 4(x+5)+8geq5(x+2)

$$4 ( x + 5 ) + 8 \geq 5 ( x + 2 )$$

Whakaoti mō x

$$x\leq 18$$

Ngā Upane Otinga

Whakamahia te āhuatanga tohatoha hei whakarea te 4 ki te x+5.

$$4x+20+8\geq 5\left(x+2\right)$$

Tāpirihia te 20 ki te 8, ka 28.

$$4x+28\geq 5\left(x+2\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te 5 ki te x+2.

$$4x+28\geq 5x+10$$

Tangohia te 5x mai i ngā taha e rua.

$$4x+28-5x\geq 10$$

Pahekotia te 4x me -5x, ka -x.

$$-x+28\geq 10$$

Tangohia te 28 mai i ngā taha e rua.

$$-x\geq 10-28$$

Tangohia te 28 i te 10, ka -18.

$$-x\geq -18$$

Whakawehea ngā taha e rua ki te -1. I te mea he tōraro a -1, ka huri te ahunga koreōrite.

$$x\leq \frac{-18}{-1}$$

Ka taea te hautanga \frac{-18}{-1} te whakamāmā ki te 18 mā te tango tahi i te tohu tōraro i te taurunga me te tauraro.

$$x\leq 18$$