Whakaoti i te 3x.3x=3x

$$3x.3x=3x$$

Whakaoti mō x

$$x = \frac{10}{3} = 3\frac{1}{3} \approx 3.333333333$$

$$x=0$$

Ngā Upane Whakamahi Tauwehe

Me whakakore te 3 ki ngā taha e rua.

$$x\times 0.3x=x$$

Whakareatia te x ki te x, ka x^{2}.

$$x^{2}\times 0.3=x$$

Tangohia te x mai i ngā taha e rua.

$$x^{2}\times 0.3-x=0$$

Tauwehea te x.

$$x\left(0.3x-1\right)=0$$

Hei kimi otinga whārite, me whakaoti te x=0 me te \frac{3x}{10}-1=0.

$$x=0 x=\frac{10}{3}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Me whakakore te 3 ki ngā taha e rua.

$$x\times 0.3x=x$$

Whakareatia te x ki te x, ka x^{2}.

$$x^{2}\times 0.3=x$$

Tangohia te x mai i ngā taha e rua.

$$x^{2}\times 0.3-x=0$$

Ko ngā whārite katoa o te āhua ax^{2}+bx+c=0 ka taea te whakaoti mā te whakamahi i te tikanga tātai pūrua: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. E rua ngā otinga ka puta i te tikanga tātai pūrua, ko tētahi ina he tāpiri a ±, ā, ko tētahi ina he tango.

$$0.3x^{2}-x=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 0.3 mō a, -1 mō b, me 0 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{-\left(-1\right)±\sqrt{1}}{2\times 0.3}$$

Tuhia te pūtakerua o te 1.

$$x=\frac{-\left(-1\right)±1}{2\times 0.3}$$

Ko te tauaro o -1 ko 1.

$$x=\frac{1±1}{2\times 0.3}$$

Whakareatia 2 ki te 0.3.

$$x=\frac{1±1}{0.6}$$

Nā, me whakaoti te whārite x=\frac{1±1}{0.6} ina he tāpiri te ±. Tāpiri 1 ki te 1.

$$x=\frac{2}{0.6}$$

Whakawehe 2 ki te 0.6 mā te whakarea 2 ki te tau huripoki o 0.6.

$$x=\frac{10}{3}$$

Nā, me whakaoti te whārite x=\frac{1±1}{0.6} ina he tango te ±. Tango 1 mai i 1.

$$x=\frac{0}{0.6}$$

Whakawehe 0 ki te 0.6 mā te whakarea 0 ki te tau huripoki o 0.6.

$$x=0$$

Kua oti te whārite te whakatau.

$$x=\frac{10}{3} x=0$$

Ngā Upane mō te Whakaoti i te Pūrua

Me whakakore te 3 ki ngā taha e rua.

$$x\times 0.3x=x$$

Whakareatia te x ki te x, ka x^{2}.

$$x^{2}\times 0.3=x$$

Tangohia te x mai i ngā taha e rua.

$$x^{2}\times 0.3-x=0$$

Ko ngā whārite pūrua pēnei i tēnei nā ka taea te whakaoti mā te whakaoti i te pūrua. Hei whakaoti i te pūrua, ko te whārite me mātua tuhi ki te āhua x^{2}+bx=c.

$$0.3x^{2}-x=0$$

Whakawehea ngā taha e rua o te whārite ki te 0.3, he ōrite ki te whakarea i ngā taha e rua ki te tau huripoki o te hautanga.

$$\frac{0.3x^{2}-x}{0.3}=\frac{0}{0.3}$$

Mā te whakawehe ki te 0.3 ka wetekia te whakareanga ki te 0.3.

$$x^{2}+\left(-\frac{1}{0.3}\right)x=\frac{0}{0.3}$$

Whakawehe -1 ki te 0.3 mā te whakarea -1 ki te tau huripoki o 0.3.

$$x^{2}-\frac{10}{3}x=\frac{0}{0.3}$$

Whakawehe 0 ki te 0.3 mā te whakarea 0 ki te tau huripoki o 0.3.

$$x^{2}-\frac{10}{3}x=0$$

Whakawehea te -\frac{10}{3}, te tau whakarea o te kīanga tau x, ki te 2 kia riro ai te -\frac{5}{3}. Nā, tāpiria te pūrua o te -\frac{5}{3} ki ngā taha e rua o te whārite. Mā konei e pūrua tika tonu ai te taha mauī o te whārite.

$$x^{2}-\frac{10}{3}x+\left(-\frac{5}{3}\right)^{2}=\left(-\frac{5}{3}\right)^{2}$$

Pūruatia -\frac{5}{3} mā te pūrua i te taurunga me te tauraro o te hautanga.

$$x^{2}-\frac{10}{3}x+\frac{25}{9}=\frac{25}{9}$$

Tauwehea x^{2}-\frac{10}{3}x+\frac{25}{9}. Ko te tikanga pūnoa, ina ko x^{2}+bx+c he pūrua tika pūrua tika pū, ka taea taua mea te tauwehea i ngā wā katoa hei \left(x+\frac{b}{2}\right)^{2}.

$$\left(x-\frac{5}{3}\right)^{2}=\frac{25}{9}$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$\sqrt{\left(x-\frac{5}{3}\right)^{2}}=\sqrt{\frac{25}{9}}$$

Whakarūnātia.

$$x-\frac{5}{3}=\frac{5}{3} x-\frac{5}{3}=-\frac{5}{3}$$

Me tāpiri \frac{5}{3} ki ngā taha e rua o te whārite.

$$x=\frac{10}{3} x=0$$