Whakaoti i te 384400=0.00001*2^x

$$384400 = 0.00001 \cdot 2 ^ { x }$$

Whakaoti mō x

$$x=\log_{2}\left(38440000000\right)\approx 35.161889285$$

Ngā Upane e Whakamahi ana i te Tautuhinga o te Taupū Kōaro

Whakawehea ngā taha e rua ki te 0.00001.

$$\frac{384400}{0.00001}=2^{x}$$

Whakarohaina te \frac{384400}{0.00001} mā te whakarea i te taurunga me te tauraro ki te 100000. Ka whakawehea he tau ki te tahi, hua ai ko ia anō.

$$38440000000=2^{x}$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$2^{x}=38440000000$$

Tuhia te tau taupū kōaro o ngā taha e rua o te whārite.

$$\log(2^{x})=\log(38440000000)$$

Ko te taupū kōaro o tētahi tau ka hīkina ki tētahi pū ko te pū whakarea ki te taupū kōaro o taua tau.

$$x\log(2)=\log(38440000000)$$

Whakawehea ngā taha e rua ki te \log(2).

$$x=\frac{\log(38440000000)}{\log(2)}$$

Mā te tikanga tātai huri pūtake \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).

$$x=\log_{2}\left(38440000000\right)$$

Whakaoti mō x (complex solution)

$$x=\frac{i\times 2\pi n_{1}}{\ln(2)}+\log_{2}\left(38440000000\right)$$

$$n_{1}\in \mathrm{Z}$$