Whakaoti i te 3800=1.23^x

$$3800 = 1.23 ^ { x }$$

Whakaoti mō x

$$x=\log_{1.23}\left(3800\right)\approx 39.817353422$$

Ngā Upane e Whakamahi ana i te Tautuhinga o te Taupū Kōaro

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$1.23^{x}=3800$$

Tuhia te tau taupū kōaro o ngā taha e rua o te whārite.

$$\log(1.23^{x})=\log(3800)$$

Ko te taupū kōaro o tētahi tau ka hīkina ki tētahi pū ko te pū whakarea ki te taupū kōaro o taua tau.

$$x\log(1.23)=\log(3800)$$

Whakawehea ngā taha e rua ki te \log(1.23).

$$x=\frac{\log(3800)}{\log(1.23)}$$

Mā te tikanga tātai huri pūtake \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).

$$x=\log_{1.23}\left(3800\right)$$

Whakaoti mō x (complex solution)

$$x=\frac{i\times 2\pi n_{1}}{\ln(1.23)}+\log_{1.23}\left(3800\right)$$

$$n_{1}\in \mathrm{Z}$$