Whakaoti i te 34(x-1)-12(2x-2)=7(05-x)+2(225+3x)

$$34(x-1)-12(2x-2)=7(05-x)+2(225+3x)$$

Whakaoti mō x

$$x = \frac{460}{11} = 41\frac{9}{11} \approx 41.818181818$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te 34 ki te x-1.

$$34x-34-12\left(2x-2\right)=7\left(0\times 5-x\right)+2\left(225+3x\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te -12 ki te 2x-2.

$$34x-34-24x+24=7\left(0\times 5-x\right)+2\left(225+3x\right)$$

Pahekotia te 34x me -24x, ka 10x.

$$10x-34+24=7\left(0\times 5-x\right)+2\left(225+3x\right)$$

Tāpirihia te -34 ki te 24, ka -10.

$$10x-10=7\left(0\times 5-x\right)+2\left(225+3x\right)$$

Whakareatia te 0 ki te 5, ka 0.

$$10x-10=7\left(0-x\right)+2\left(225+3x\right)$$

Ko te tau i tāpiria he kore ka hua koia tonu.

$$10x-10=7\left(-1\right)x+2\left(225+3x\right)$$

Whakareatia te 7 ki te -1, ka -7.

$$10x-10=-7x+2\left(225+3x\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te 2 ki te 225+3x.

$$10x-10=-7x+450+6x$$

Pahekotia te -7x me 6x, ka -x.

$$10x-10=-x+450$$

Me tāpiri te x ki ngā taha e rua.

$$10x-10+x=450$$

Pahekotia te 10x me x, ka 11x.

$$11x-10=450$$

Me tāpiri te 10 ki ngā taha e rua.

$$11x=450+10$$

Tāpirihia te 450 ki te 10, ka 460.

$$11x=460$$

Whakawehea ngā taha e rua ki te 11.

$$x=\frac{460}{11}$$