Whakaoti i te 33t^4+1826t^2-750779=0

$$33 t ^ { 4 } + 1826 t ^ { 2 } - 750779 = 0$$

Whakaoti mō t

$$t = -\frac{\sqrt{66 \sqrt{6402319} - 30129}}{33} \approx -11.21087248$$

$$t = \frac{\sqrt{66 \sqrt{6402319} - 30129}}{33} \approx 11.21087248$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Whakakapia te t mō te t^{2}.

$$33t^{2}+1826t-750779=0$$

Ka taea ngā whārite katoa o te momo ax^{2}+bx+c=0 te whakaoti mā te ture pūrua: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Whakakapia te 33 mō te a, te 1826 mō te b, me te -750779 mō te c i te ture pūrua.

$$t=\frac{-1826±\sqrt{1826^{2}-4\times 33\left(-750779\right)}}{2\times 33}$$

Mahia ngā tātaitai.

$$t=\frac{-1826±4\sqrt{6402319}}{66}$$

Whakaotia te whārite t=\frac{-1826±4\sqrt{6402319}}{66} ina he tōrunga te ±, ina he tōraro te ±.

$$t=\frac{2\sqrt{6402319}}{33}-\frac{83}{3} t=-\frac{2\sqrt{6402319}}{33}-\frac{83}{3}$$

I te mea ko t=t^{2}, ka riro ngā otinga mā te arotake i te t=±\sqrt{t} mō t tōrunga.

$$t=\sqrt{\frac{2\sqrt{6402319}}{33}-\frac{83}{3}} t=-\sqrt{\frac{2\sqrt{6402319}}{33}-\frac{83}{3}}$$