Whakaoti i te 3,6:(51/5-7)+(1/2)^3*0,4^2=

$$3,6 : ( 5 \frac { 1 } { 5 } - 7 ) + ( \frac { 1 } { 2 } ) ^ { 3 } \cdot 0,4 ^ { 2 } =$$

Kōmaka

$$-\frac{10}{3},3,16$$

Ngā Upane Otinga

Whakareatia te 5 ki te 5, ka 25.

$$sort(3,\frac{6}{\frac{25+1}{5}-7}+\left(\frac{1}{2}\right)^{3}\times 0,4^{2})$$

Tāpirihia te 25 ki te 1, ka 26.

$$sort(3,\frac{6}{\frac{26}{5}-7}+\left(\frac{1}{2}\right)^{3}\times 0,4^{2})$$

Me tahuri te 7 ki te hautau \frac{35}{5}.

$$sort(3,\frac{6}{\frac{26}{5}-\frac{35}{5}}+\left(\frac{1}{2}\right)^{3}\times 0,4^{2})$$

Tā te mea he rite te tauraro o \frac{26}{5} me \frac{35}{5}, me tango rāua mā te tango i ō raua taurunga.

$$sort(3,\frac{6}{\frac{26-35}{5}}+\left(\frac{1}{2}\right)^{3}\times 0,4^{2})$$

Tangohia te 35 i te 26, ka -9.

$$sort(3,\frac{6}{-\frac{9}{5}}+\left(\frac{1}{2}\right)^{3}\times 0,4^{2})$$

Whakawehe 6 ki te -\frac{9}{5} mā te whakarea 6 ki te tau huripoki o -\frac{9}{5}.

$$sort(3,6\left(-\frac{5}{9}\right)+\left(\frac{1}{2}\right)^{3}\times 0,4^{2})$$

Tuhia te 6\left(-\frac{5}{9}\right) hei hautanga kotahi.

$$sort(3,\frac{6\left(-5\right)}{9}+\left(\frac{1}{2}\right)^{3}\times 0,4^{2})$$

Whakareatia te 6 ki te -5, ka -30.

$$sort(3,\frac{-30}{9}+\left(\frac{1}{2}\right)^{3}\times 0,4^{2})$$

Whakahekea te hautanga \frac{-30}{9} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 3.

$$sort(3,-\frac{10}{3}+\left(\frac{1}{2}\right)^{3}\times 0,4^{2})$$

Tātaihia te \frac{1}{2} mā te pū o 3, kia riro ko \frac{1}{8}.

$$sort(3,-\frac{10}{3}+\frac{1}{8}\times 0,4^{2})$$

Whakareatia te \frac{1}{8} ki te 0, ka 0.

$$sort(3,-\frac{10}{3}+0,4^{2})$$

Tāpirihia te -\frac{10}{3} ki te 0, ka -\frac{10}{3}.

$$sort(3,-\frac{10}{3},4^{2})$$

Tātaihia te 4 mā te pū o 2, kia riro ko 16.

$$sort(3,-\frac{10}{3},16)$$

Tahuritia ngā tau ā-ira i te rārangi 3,-\frac{10}{3},16 ki ngā hautanga.

$$3,-\frac{10}{3},16$$

Hei kōmaka i te rārangi, me tīmata mai i tētahi huānga 3 kotahi.

$$3$$

Me kōkuhu te -\frac{10}{3} ki te tauwāhi tika i te rārangi hōu.

$$-\frac{10}{3},3$$

Me kōkuhu te 16 ki te tauwāhi tika i te rārangi hōu.

$$-\frac{10}{3},3,16$$

Aromātai

$$3,-\frac{10}{3},16$$