Whakaoti i te 3y^2=48

$$3 y ^ { 2 } = 48$$

Whakaoti mō y

$$y=4$$

$$y=-4$$

Ngā Hipanga Whakamahi Rerekētanga o ngā Pūrua

Whakawehea ngā taha e rua ki te 3.

$$y^{2}=\frac{48}{3}$$

Whakawehea te 48 ki te 3, kia riro ko 16.

$$y^{2}=16$$

Tangohia te 16 mai i ngā taha e rua.

$$y^{2}-16=0$$

Whakaarohia te y^{2}-16. Tuhia anō te y^{2}-16 hei y^{2}-4^{2}. Ka taea te rerekētanga o ngā pūrua te whakatauwehe mā te ture: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).

$$\left(y-4\right)\left(y+4\right)=0$$

Hei kimi otinga whārite, me whakaoti te y-4=0 me te y+4=0.

$$y=4 y=-4$$

Ngā Upane mā te Kimi Pūtakerua

Whakawehea ngā taha e rua ki te 3.

$$y^{2}=\frac{48}{3}$$

Whakawehea te 48 ki te 3, kia riro ko 16.

$$y^{2}=16$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$y=4 y=-4$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Whakawehea ngā taha e rua ki te 3.

$$y^{2}=\frac{48}{3}$$

Whakawehea te 48 ki te 3, kia riro ko 16.

$$y^{2}=16$$

Tangohia te 16 mai i ngā taha e rua.

$$y^{2}-16=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me -16 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$y=\frac{0±\sqrt{0^{2}-4\left(-16\right)}}{2}$$

Pūrua 0.

$$y=\frac{0±\sqrt{-4\left(-16\right)}}{2}$$

Whakareatia -4 ki te -16.

$$y=\frac{0±\sqrt{64}}{2}$$

Tuhia te pūtakerua o te 64.

$$y=\frac{0±8}{2}$$

Nā, me whakaoti te whārite y=\frac{0±8}{2} ina he tāpiri te ±. Whakawehe 8 ki te 2.

$$y=4$$

Nā, me whakaoti te whārite y=\frac{0±8}{2} ina he tango te ±. Whakawehe -8 ki te 2.

$$y=-4$$

Kua oti te whārite te whakatau.

$$y=4 y=-4$$