Whakaoti i te 3y+4x^2=sqrt{15}

$$3 y + 4 x ^ { 2 } = \sqrt { 15 }$$

Whakaoti mō y

$$y=\frac{-4x^{2}+\sqrt{15}}{3}$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tangohia te 4x^{2} mai i ngā taha e rua.

$$3y=\sqrt{15}-4x^{2}$$

He hanga arowhānui tō te whārite.

$$3y=-4x^{2}+\sqrt{15}$$

Whakawehea ngā taha e rua ki te 3.

$$\frac{3y}{3}=\frac{-4x^{2}+\sqrt{15}}{3}$$

Mā te whakawehe ki te 3 ka wetekia te whakareanga ki te 3.

$$y=\frac{-4x^{2}+\sqrt{15}}{3}$$

Whakaoti mō x (complex solution)

$$x=-\frac{\sqrt{-3y+\sqrt{15}}}{2}$$

$$x=\frac{\sqrt{-3y+\sqrt{15}}}{2}$$

Whakaoti mō x

$$x=\frac{\sqrt{-3y+\sqrt{15}}}{2}$$

$$x=-\frac{\sqrt{-3y+\sqrt{15}}}{2}\text{, }y\leq \frac{\sqrt{15}}{3}$$