Whakaoti i te 3x-5=3x^2-2x

$$3 x - 5 = 3 x ^ { 2 } - 2 x$$

Whakaoti mō x (complex solution)

$$x=\frac{-\sqrt{35}i+5}{6}\approx 0.833333333-0.986013297i$$

$$x=\frac{5+\sqrt{35}i}{6}\approx 0.833333333+0.986013297i$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Tangohia te 3x^{2} mai i ngā taha e rua.

$$3x-5-3x^{2}=-2x$$

Me tāpiri te 2x ki ngā taha e rua.

$$3x-5-3x^{2}+2x=0$$

Pahekotia te 3x me 2x, ka 5x.

$$5x-5-3x^{2}=0$$

Ko ngā whārite katoa o te āhua ax^{2}+bx+c=0 ka taea te whakaoti mā te whakamahi i te tikanga tātai pūrua: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. E rua ngā otinga ka puta i te tikanga tātai pūrua, ko tētahi ina he tāpiri a ±, ā, ko tētahi ina he tango.

$$-3x^{2}+5x-5=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi -3 mō a, 5 mō b, me -5 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{-5±\sqrt{5^{2}-4\left(-3\right)\left(-5\right)}}{2\left(-3\right)}$$

Pūrua 5.

$$x=\frac{-5±\sqrt{25-4\left(-3\right)\left(-5\right)}}{2\left(-3\right)}$$

Whakareatia -4 ki te -3.

$$x=\frac{-5±\sqrt{25+12\left(-5\right)}}{2\left(-3\right)}$$

Whakareatia 12 ki te -5.

$$x=\frac{-5±\sqrt{25-60}}{2\left(-3\right)}$$

Tāpiri 25 ki te -60.

$$x=\frac{-5±\sqrt{-35}}{2\left(-3\right)}$$

Tuhia te pūtakerua o te -35.

$$x=\frac{-5±\sqrt{35}i}{2\left(-3\right)}$$

Whakareatia 2 ki te -3.

$$x=\frac{-5±\sqrt{35}i}{-6}$$

Nā, me whakaoti te whārite x=\frac{-5±\sqrt{35}i}{-6} ina he tāpiri te ±. Tāpiri -5 ki te i\sqrt{35}.

$$x=\frac{-5+\sqrt{35}i}{-6}$$

Whakawehe -5+i\sqrt{35} ki te -6.

$$x=\frac{-\sqrt{35}i+5}{6}$$

Nā, me whakaoti te whārite x=\frac{-5±\sqrt{35}i}{-6} ina he tango te ±. Tango i\sqrt{35} mai i -5.

$$x=\frac{-\sqrt{35}i-5}{-6}$$

Whakawehe -5-i\sqrt{35} ki te -6.

$$x=\frac{5+\sqrt{35}i}{6}$$

Kua oti te whārite te whakatau.

$$x=\frac{-\sqrt{35}i+5}{6} x=\frac{5+\sqrt{35}i}{6}$$

Ngā Upane mō te Whakaoti i te Pūrua

Tangohia te 3x^{2} mai i ngā taha e rua.

$$3x-5-3x^{2}=-2x$$

Me tāpiri te 2x ki ngā taha e rua.

$$3x-5-3x^{2}+2x=0$$

Pahekotia te 3x me 2x, ka 5x.

$$5x-5-3x^{2}=0$$

Me tāpiri te 5 ki ngā taha e rua. Ko te tau i tāpiria he kore ka hua koia tonu.

$$5x-3x^{2}=5$$

Ko ngā whārite pūrua pēnei i tēnei nā ka taea te whakaoti mā te whakaoti i te pūrua. Hei whakaoti i te pūrua, ko te whārite me mātua tuhi ki te āhua x^{2}+bx=c.

$$-3x^{2}+5x=5$$

Whakawehea ngā taha e rua ki te -3.

$$\frac{-3x^{2}+5x}{-3}=\frac{5}{-3}$$

Mā te whakawehe ki te -3 ka wetekia te whakareanga ki te -3.

$$x^{2}+\frac{5}{-3}x=\frac{5}{-3}$$

Whakawehe 5 ki te -3.

$$x^{2}-\frac{5}{3}x=\frac{5}{-3}$$

Whakawehe 5 ki te -3.

$$x^{2}-\frac{5}{3}x=-\frac{5}{3}$$

Whakawehea te -\frac{5}{3}, te tau whakarea o te kīanga tau x, ki te 2 kia riro ai te -\frac{5}{6}. Nā, tāpiria te pūrua o te -\frac{5}{6} ki ngā taha e rua o te whārite. Mā konei e pūrua tika tonu ai te taha mauī o te whārite.

$$x^{2}-\frac{5}{3}x+\left(-\frac{5}{6}\right)^{2}=-\frac{5}{3}+\left(-\frac{5}{6}\right)^{2}$$

Pūruatia -\frac{5}{6} mā te pūrua i te taurunga me te tauraro o te hautanga.

$$x^{2}-\frac{5}{3}x+\frac{25}{36}=-\frac{5}{3}+\frac{25}{36}$$

Tāpiri -\frac{5}{3} ki te \frac{25}{36} mā te kimi i te tauraro pātahi me te tāpiri i ngā taurunga. Ka whakaiti i te hautanga ki ngā kīanga tau iti rawa e taea ana.

$$x^{2}-\frac{5}{3}x+\frac{25}{36}=-\frac{35}{36}$$

Tauwehea x^{2}-\frac{5}{3}x+\frac{25}{36}. Ko te tikanga pūnoa, ina ko x^{2}+bx+c he pūrua tika pūrua tika pū, ka taea taua mea te tauwehea i ngā wā katoa hei \left(x+\frac{b}{2}\right)^{2}.

$$\left(x-\frac{5}{6}\right)^{2}=-\frac{35}{36}$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$\sqrt{\left(x-\frac{5}{6}\right)^{2}}=\sqrt{-\frac{35}{36}}$$

Whakarūnātia.

$$x-\frac{5}{6}=\frac{\sqrt{35}i}{6} x-\frac{5}{6}=-\frac{\sqrt{35}i}{6}$$

Me tāpiri \frac{5}{6} ki ngā taha e rua o te whārite.

$$x=\frac{5+\sqrt{35}i}{6} x=\frac{-\sqrt{35}i+5}{6}$$