Whakaoti i te 3x-2sqrt{9x}=0

$$3 x - 2 \sqrt { 9 x } = 0$$

Whakaoti mō x

$$x=4$$

$$x=0$$

Ngā Upane Otinga

Me tango 3x mai i ngā taha e rua o te whārite.

$$-2\sqrt{9x}=-3x$$

Pūruatia ngā taha e rua o te whārite.

$$\left(-2\sqrt{9x}\right)^{2}=\left(-3x\right)^{2}$$

Whakarohaina te \left(-2\sqrt{9x}\right)^{2}.

$$\left(-2\right)^{2}\left(\sqrt{9x}\right)^{2}=\left(-3x\right)^{2}$$

Tātaihia te -2 mā te pū o 2, kia riro ko 4.

$$4\left(\sqrt{9x}\right)^{2}=\left(-3x\right)^{2}$$

Tātaihia te \sqrt{9x} mā te pū o 2, kia riro ko 9x.

$$4\times 9x=\left(-3x\right)^{2}$$

Whakareatia te 4 ki te 9, ka 36.

$$36x=\left(-3x\right)^{2}$$

Whakarohaina te \left(-3x\right)^{2}.

$$36x=\left(-3\right)^{2}x^{2}$$

Tātaihia te -3 mā te pū o 2, kia riro ko 9.

$$36x=9x^{2}$$

Tangohia te 9x^{2} mai i ngā taha e rua.

$$36x-9x^{2}=0$$

Tauwehea te x.

$$x\left(36-9x\right)=0$$

Hei kimi otinga whārite, me whakaoti te x=0 me te 36-9x=0.

$$x=0 x=4$$

Whakakapia te 0 mō te x i te whārite 3x-2\sqrt{9x}=0.

$$3\times 0-2\sqrt{9\times 0}=0$$

Whakarūnātia. Ko te uara x=0 kua ngata te whārite.

$$0=0$$

Whakakapia te 4 mō te x i te whārite 3x-2\sqrt{9x}=0.

$$3\times 4-2\sqrt{9\times 4}=0$$

Whakarūnātia. Ko te uara x=4 kua ngata te whārite.

$$0=0$$

Rārangihia ngā rongoā katoa o -2\sqrt{9x}=-3x.

$$x=0 x=4$$