Whakaoti i te 3x-(k+1)y=20text{and}(k+2)x-10y=40

$$3 x - ( k + 1 ) y = 20 \text { and } ( k + 2 ) x - 10 y = 40$$

Whakaoti mō x, y (complex solution)

$$\left\{\begin{matrix}x=\frac{40}{k+7}\text{, }y=-\frac{20}{k+7}\text{, }&k\neq -7\\x=\frac{5\left(y+4\right)}{3}\text{, }y\in \mathrm{C}\text{, }&k=4\end{matrix}\right.$$

Ngā Upane e Whakamahi ana i te Whakakapinga

Whakaarohia te whārite tuatahi. Whakamahia te āhuatanga tohatoha hei whakarea te k+1 ki te y.

$$3x-\left(ky+y\right)=20$$

Hei kimi i te tauaro o ky+y, kimihia te tauaro o ia taurangi.

$$3x-ky-y=20$$

Pahekotia ngā kīanga tau katoa e whai ana i te x,y.

$$3x+\left(-k-1\right)y=20$$

Whakaarohia te whārite tuarua. Whakamahia te āhuatanga tohatoha hei whakarea te k+2 ki te x.

$$kx+2x-10y=40$$

Pahekotia ngā kīanga tau katoa e whai ana i te x,y.

$$\left(k+2\right)x-10y=40$$

Hei whakaoti i ētahi whārite takirua mā te whakakapinga, me whakaoti tētahi whārite i te tuatahi mō tētahi o ngā taurangi. Ka whakakapi i te otinga mō taua taurangi ki tērā o ngā whārite.

$$3x+\left(-k-1\right)y=20,\left(k+2\right)x-10y=40$$

Kōwhiria tētahi o ngā whārite ka whakaotia mō te x mā te wehe i te x i te taha mauī o te tohu ōrite.

$$3x+\left(-k-1\right)y=20$$

Me tāpiri \left(k+1\right)y ki ngā taha e rua o te whārite.

$$3x=\left(k+1\right)y+20$$

Whakawehea ngā taha e rua ki te 3.

$$x=\frac{1}{3}\left(\left(k+1\right)y+20\right)$$

Whakareatia \frac{1}{3} ki te yk+y+20.

$$x=\frac{k+1}{3}y+\frac{20}{3}$$

Whakakapia te \frac{yk+y+20}{3} mō te x ki tērā atu whārite, \left(k+2\right)x-10y=40.

$$\left(k+2\right)\left(\frac{k+1}{3}y+\frac{20}{3}\right)-10y=40$$

Whakareatia k+2 ki te \frac{yk+y+20}{3}.

$$\frac{\left(k+1\right)\left(k+2\right)}{3}y+\frac{20k+40}{3}-10y=40$$

Tāpiri \frac{\left(k+2\right)\left(k+1\right)y}{3} ki te -10y.

$$\frac{\left(k-4\right)\left(k+7\right)}{3}y+\frac{20k+40}{3}=40$$

Me tango \frac{40+20k}{3} mai i ngā taha e rua o te whārite.

$$\frac{\left(k-4\right)\left(k+7\right)}{3}y=\frac{80-20k}{3}$$

Whakawehea ngā taha e rua ki te \frac{\left(-4+k\right)\left(7+k\right)}{3}.

$$y=-\frac{20}{k+7}$$

Whakaurua te -\frac{20}{7+k} mō y ki x=\frac{k+1}{3}y+\frac{20}{3}. I te mea kotahi anake te taurangi kei te whārite i puta, ka taea e koe te whakaoti mō x hāngai tonu.

$$x=\frac{k+1}{3}\left(-\frac{20}{k+7}\right)+\frac{20}{3}$$

Whakareatia \frac{k+1}{3} ki te -\frac{20}{7+k}.

$$x=-\frac{20\left(k+1\right)}{3\left(k+7\right)}+\frac{20}{3}$$

Tāpiri \frac{20}{3} ki te -\frac{20\left(k+1\right)}{3\left(7+k\right)}.

$$x=\frac{40}{k+7}$$

Kua oti te pūnaha te whakatau.

$$x=\frac{40}{k+7},y=-\frac{20}{k+7}$$

Ngā Upane e Whakamahi ana i Ngā Poukapa

Whakaarohia te whārite tuatahi. Whakamahia te āhuatanga tohatoha hei whakarea te k+1 ki te y.

$$3x-\left(ky+y\right)=20$$

Hei kimi i te tauaro o ky+y, kimihia te tauaro o ia taurangi.

$$3x-ky-y=20$$

Pahekotia ngā kīanga tau katoa e whai ana i te x,y.

$$3x+\left(-k-1\right)y=20$$

Whakaarohia te whārite tuarua. Whakamahia te āhuatanga tohatoha hei whakarea te k+2 ki te x.

$$kx+2x-10y=40$$

Pahekotia ngā kīanga tau katoa e whai ana i te x,y.

$$\left(k+2\right)x-10y=40$$

Tuhia ngā whārite ki te tānga ngahuru ka whakamahi i ngā poukapa hei whakaoti i te pūnaha o ngā whārite.

$$3x+\left(-k-1\right)y=20,\left(k+2\right)x-10y=40$$

Tuhia ngā whārite ki te tikanga tātai poukapa.

$$\left(\begin{matrix}3&-k-1\\k+2&-10\end{matrix}\right)\left(\begin{matrix}x\\y\end{matrix}\right)=\left(\begin{matrix}20\\40\end{matrix}\right)$$

Whakarea mauī i te whārite ki te poukapa kōaro o \left(\begin{matrix}3&-k-1\\k+2&-10\end{matrix}\right).

$$inverse(\left(\begin{matrix}3&-k-1\\k+2&-10\end{matrix}\right))\left(\begin{matrix}3&-k-1\\k+2&-10\end{matrix}\right)\left(\begin{matrix}x\\y\end{matrix}\right)=inverse(\left(\begin{matrix}3&-k-1\\k+2&-10\end{matrix}\right))\left(\begin{matrix}20\\40\end{matrix}\right)$$

Ko te hua o tētahi poukapa me te kōaro ko te poukapa tuakiri.

$$\left(\begin{matrix}1&0\\0&1\end{matrix}\right)\left(\begin{matrix}x\\y\end{matrix}\right)=inverse(\left(\begin{matrix}3&-k-1\\k+2&-10\end{matrix}\right))\left(\begin{matrix}20\\40\end{matrix}\right)$$

Whakareatia ngā poukapa kei te taha mauī o te tohu ōrite.

$$\left(\begin{matrix}x\\y\end{matrix}\right)=inverse(\left(\begin{matrix}3&-k-1\\k+2&-10\end{matrix}\right))\left(\begin{matrix}20\\40\end{matrix}\right)$$

Mō te poukapa 2\times 2 \left(\begin{matrix}a&b\\c&d\end{matrix}\right), ko te \left(\begin{matrix}\frac{d}{ad-bc}&\frac{-b}{ad-bc}\\\frac{-c}{ad-bc}&\frac{a}{ad-bc}\end{matrix}\right) te poukapa kōaro, nō reira ka taea te tuhi anō te whārite poukapa hei rapanga whakarea poukapa.

$$\left(\begin{matrix}x\\y\end{matrix}\right)=\left(\begin{matrix}-\frac{10}{3\left(-10\right)-\left(-k-1\right)\left(k+2\right)}&-\frac{-k-1}{3\left(-10\right)-\left(-k-1\right)\left(k+2\right)}\\-\frac{k+2}{3\left(-10\right)-\left(-k-1\right)\left(k+2\right)}&\frac{3}{3\left(-10\right)-\left(-k-1\right)\left(k+2\right)}\end{matrix}\right)\left(\begin{matrix}20\\40\end{matrix}\right)$$

Mahia ngā tātaitanga.

$$\left(\begin{matrix}x\\y\end{matrix}\right)=\left(\begin{matrix}-\frac{10}{\left(k-4\right)\left(k+7\right)}&\frac{k+1}{\left(k-4\right)\left(k+7\right)}\\-\frac{k+2}{\left(k-4\right)\left(k+7\right)}&\frac{3}{\left(k-4\right)\left(k+7\right)}\end{matrix}\right)\left(\begin{matrix}20\\40\end{matrix}\right)$$

Whakareatia ngā poukapa.

$$\left(\begin{matrix}x\\y\end{matrix}\right)=\left(\begin{matrix}\left(-\frac{10}{\left(k-4\right)\left(k+7\right)}\right)\times 20+\frac{k+1}{\left(k-4\right)\left(k+7\right)}\times 40\\\left(-\frac{k+2}{\left(k-4\right)\left(k+7\right)}\right)\times 20+\frac{3}{\left(k-4\right)\left(k+7\right)}\times 40\end{matrix}\right)$$

Mahia ngā tātaitanga.

$$\left(\begin{matrix}x\\y\end{matrix}\right)=\left(\begin{matrix}\frac{40}{k+7}\\-\frac{20}{k+7}\end{matrix}\right)$$

Tangohia ngā huānga poukapa x me y.

$$x=\frac{40}{k+7},y=-\frac{20}{k+7}$$

Ngā Upane e Whakamahi i te Tangohanga

Whakaarohia te whārite tuatahi. Whakamahia te āhuatanga tohatoha hei whakarea te k+1 ki te y.

$$3x-\left(ky+y\right)=20$$

Hei kimi i te tauaro o ky+y, kimihia te tauaro o ia taurangi.

$$3x-ky-y=20$$

Pahekotia ngā kīanga tau katoa e whai ana i te x,y.

$$3x+\left(-k-1\right)y=20$$

Whakaarohia te whārite tuarua. Whakamahia te āhuatanga tohatoha hei whakarea te k+2 ki te x.

$$kx+2x-10y=40$$

Pahekotia ngā kīanga tau katoa e whai ana i te x,y.

$$\left(k+2\right)x-10y=40$$

Hei whakaoti mā te tangohanga, ko ngā tau whakarea o tētahi o ngā taurangi me mātua ōrite i ngā whārite e rua kia whakakorehia ai te taurangi ina tangohia tētahi whārite mai i tētahi atu.

$$3x+\left(-k-1\right)y=20,\left(k+2\right)x-10y=40$$

Kia ōrite ai a 3x me \left(k+2\right)x, whakareatia ngā kīanga tau katoa kei ia taha o te whārite tuatahi ki te k+2 me ngā kīanga tau katoa kei ia taha o te whārite tuarua ki te 3.

$$\left(k+2\right)\times 3x+\left(k+2\right)\left(-k-1\right)y=\left(k+2\right)\times 20,3\left(k+2\right)x+3\left(-10\right)y=3\times 40$$

Whakarūnātia.

$$\left(3k+6\right)x+\left(-\left(k+1\right)\left(k+2\right)\right)y=20k+40,\left(3k+6\right)x-30y=120$$

Me tango \left(3k+6\right)x-30y=120 mai i \left(3k+6\right)x+\left(-\left(k+1\right)\left(k+2\right)\right)y=20k+40 mā te tango i ngā kīanga tau ōrite i ia taha o te tohu ōrite.

$$\left(3k+6\right)x+\left(-3k-6\right)x+\left(-\left(k+1\right)\left(k+2\right)\right)y+30y=20k+40-120$$

Tāpiri 3\left(2+k\right)x ki te -6x-3xk. Ka whakakore atu ngā kupu 3\left(2+k\right)x me -6x-3xk, ka toe he whārite me tētahi taurangi kotahi ka taea te whakaoti.

$$\left(-\left(k+1\right)\left(k+2\right)\right)y+30y=20k+40-120$$

Tāpiri -\left(k+2\right)\left(k+1\right)y ki te 30y.

$$\left(4-k\right)\left(k+7\right)y=20k+40-120$$

Tāpiri 20k+40 ki te -120.

$$\left(4-k\right)\left(k+7\right)y=20k-80$$

Whakawehea ngā taha e rua ki te \left(4-k\right)\left(7+k\right).

$$y=-\frac{20}{k+7}$$

Whakaurua te -\frac{20}{7+k} mō y ki \left(k+2\right)x-10y=40. I te mea kotahi anake te taurangi kei te whārite i puta, ka taea e koe te whakaoti mō x hāngai tonu.

$$\left(k+2\right)x-10\left(-\frac{20}{k+7}\right)=40$$

Whakareatia -10 ki te -\frac{20}{7+k}.

$$\left(k+2\right)x+\frac{200}{k+7}=40$$

Me tango \frac{200}{7+k} mai i ngā taha e rua o te whārite.

$$\left(k+2\right)x=\frac{40\left(k+2\right)}{k+7}$$

Whakawehea ngā taha e rua ki te k+2.

$$x=\frac{40}{k+7}$$

Kua oti te pūnaha te whakatau.

$$x=\frac{40}{k+7},y=-\frac{20}{k+7}$$

Whakaoti mō x, y

$$\left\{\begin{matrix}x=\frac{40}{k+7}\text{, }y=-\frac{20}{k+7}\text{, }&k\neq -7\text{ and }k\neq 4\\x=\frac{5\left(y+4\right)}{3}\text{, }y\in \mathrm{R}\text{, }&k=4\end{matrix}\right.$$

Ngā Upane e Whakamahi ana i te Whakakapinga

Whakaarohia te whārite tuatahi. Whakamahia te āhuatanga tohatoha hei whakarea te k+1 ki te y.

$$3x-\left(ky+y\right)=20$$

Hei kimi i te tauaro o ky+y, kimihia te tauaro o ia taurangi.

$$3x-ky-y=20$$

Pahekotia ngā kīanga tau katoa e whai ana i te x,y.

$$3x+\left(-k-1\right)y=20$$

Whakaarohia te whārite tuarua. Whakamahia te āhuatanga tohatoha hei whakarea te k+2 ki te x.

$$kx+2x-10y=40$$

Pahekotia ngā kīanga tau katoa e whai ana i te x,y.

$$\left(k+2\right)x-10y=40$$

Hei whakaoti i ētahi whārite takirua mā te whakakapinga, me whakaoti tētahi whārite i te tuatahi mō tētahi o ngā taurangi. Ka whakakapi i te otinga mō taua taurangi ki tērā o ngā whārite.

$$3x+\left(-k-1\right)y=20,\left(k+2\right)x-10y=40$$

Kōwhiria tētahi o ngā whārite ka whakaotia mō te x mā te wehe i te x i te taha mauī o te tohu ōrite.

$$3x+\left(-k-1\right)y=20$$

Me tāpiri \left(k+1\right)y ki ngā taha e rua o te whārite.

$$3x=\left(k+1\right)y+20$$

Whakawehea ngā taha e rua ki te 3.

$$x=\frac{1}{3}\left(\left(k+1\right)y+20\right)$$

Whakareatia \frac{1}{3} ki te yk+y+20.

$$x=\frac{k+1}{3}y+\frac{20}{3}$$

Whakakapia te \frac{yk+y+20}{3} mō te x ki tērā atu whārite, \left(k+2\right)x-10y=40.

$$\left(k+2\right)\left(\frac{k+1}{3}y+\frac{20}{3}\right)-10y=40$$

Whakareatia k+2 ki te \frac{yk+y+20}{3}.

$$\frac{\left(k+1\right)\left(k+2\right)}{3}y+\frac{20k+40}{3}-10y=40$$

Tāpiri \frac{\left(k+2\right)\left(k+1\right)y}{3} ki te -10y.

$$\frac{\left(k-4\right)\left(k+7\right)}{3}y+\frac{20k+40}{3}=40$$

Me tango \frac{40+20k}{3} mai i ngā taha e rua o te whārite.

$$\frac{\left(k-4\right)\left(k+7\right)}{3}y=\frac{80-20k}{3}$$

Whakawehea ngā taha e rua ki te \frac{\left(-4+k\right)\left(7+k\right)}{3}.

$$y=-\frac{20}{k+7}$$

Whakaurua te -\frac{20}{7+k} mō y ki x=\frac{k+1}{3}y+\frac{20}{3}. I te mea kotahi anake te taurangi kei te whārite i puta, ka taea e koe te whakaoti mō x hāngai tonu.

$$x=\frac{k+1}{3}\left(-\frac{20}{k+7}\right)+\frac{20}{3}$$

Whakareatia \frac{k+1}{3} ki te -\frac{20}{7+k}.

$$x=-\frac{20\left(k+1\right)}{3\left(k+7\right)}+\frac{20}{3}$$

Tāpiri \frac{20}{3} ki te -\frac{20\left(k+1\right)}{3\left(7+k\right)}.

$$x=\frac{40}{k+7}$$

Kua oti te pūnaha te whakatau.

$$x=\frac{40}{k+7},y=-\frac{20}{k+7}$$

Ngā Upane e Whakamahi ana i Ngā Poukapa

Whakaarohia te whārite tuatahi. Whakamahia te āhuatanga tohatoha hei whakarea te k+1 ki te y.

$$3x-\left(ky+y\right)=20$$

Hei kimi i te tauaro o ky+y, kimihia te tauaro o ia taurangi.

$$3x-ky-y=20$$

Pahekotia ngā kīanga tau katoa e whai ana i te x,y.

$$3x+\left(-k-1\right)y=20$$

Whakaarohia te whārite tuarua. Whakamahia te āhuatanga tohatoha hei whakarea te k+2 ki te x.

$$kx+2x-10y=40$$

Pahekotia ngā kīanga tau katoa e whai ana i te x,y.

$$\left(k+2\right)x-10y=40$$

Tuhia ngā whārite ki te tānga ngahuru ka whakamahi i ngā poukapa hei whakaoti i te pūnaha o ngā whārite.

$$3x+\left(-k-1\right)y=20,\left(k+2\right)x-10y=40$$

Tuhia ngā whārite ki te tikanga tātai poukapa.

$$\left(\begin{matrix}3&-k-1\\k+2&-10\end{matrix}\right)\left(\begin{matrix}x\\y\end{matrix}\right)=\left(\begin{matrix}20\\40\end{matrix}\right)$$

Whakarea mauī i te whārite ki te poukapa kōaro o \left(\begin{matrix}3&-k-1\\k+2&-10\end{matrix}\right).

$$inverse(\left(\begin{matrix}3&-k-1\\k+2&-10\end{matrix}\right))\left(\begin{matrix}3&-k-1\\k+2&-10\end{matrix}\right)\left(\begin{matrix}x\\y\end{matrix}\right)=inverse(\left(\begin{matrix}3&-k-1\\k+2&-10\end{matrix}\right))\left(\begin{matrix}20\\40\end{matrix}\right)$$

Ko te hua o tētahi poukapa me te kōaro ko te poukapa tuakiri.

$$\left(\begin{matrix}1&0\\0&1\end{matrix}\right)\left(\begin{matrix}x\\y\end{matrix}\right)=inverse(\left(\begin{matrix}3&-k-1\\k+2&-10\end{matrix}\right))\left(\begin{matrix}20\\40\end{matrix}\right)$$

Whakareatia ngā poukapa kei te taha mauī o te tohu ōrite.

$$\left(\begin{matrix}x\\y\end{matrix}\right)=inverse(\left(\begin{matrix}3&-k-1\\k+2&-10\end{matrix}\right))\left(\begin{matrix}20\\40\end{matrix}\right)$$

Mō te poukapa 2\times 2 \left(\begin{matrix}a&b\\c&d\end{matrix}\right), ko te \left(\begin{matrix}\frac{d}{ad-bc}&\frac{-b}{ad-bc}\\\frac{-c}{ad-bc}&\frac{a}{ad-bc}\end{matrix}\right) te poukapa kōaro, nō reira ka taea te tuhi anō te whārite poukapa hei rapanga whakarea poukapa.

$$\left(\begin{matrix}x\\y\end{matrix}\right)=\left(\begin{matrix}-\frac{10}{3\left(-10\right)-\left(-k-1\right)\left(k+2\right)}&-\frac{-k-1}{3\left(-10\right)-\left(-k-1\right)\left(k+2\right)}\\-\frac{k+2}{3\left(-10\right)-\left(-k-1\right)\left(k+2\right)}&\frac{3}{3\left(-10\right)-\left(-k-1\right)\left(k+2\right)}\end{matrix}\right)\left(\begin{matrix}20\\40\end{matrix}\right)$$

Mahia ngā tātaitanga.

$$\left(\begin{matrix}x\\y\end{matrix}\right)=\left(\begin{matrix}-\frac{10}{\left(k-4\right)\left(k+7\right)}&\frac{k+1}{\left(k-4\right)\left(k+7\right)}\\-\frac{k+2}{\left(k-4\right)\left(k+7\right)}&\frac{3}{\left(k-4\right)\left(k+7\right)}\end{matrix}\right)\left(\begin{matrix}20\\40\end{matrix}\right)$$

Whakareatia ngā poukapa.

$$\left(\begin{matrix}x\\y\end{matrix}\right)=\left(\begin{matrix}\left(-\frac{10}{\left(k-4\right)\left(k+7\right)}\right)\times 20+\frac{k+1}{\left(k-4\right)\left(k+7\right)}\times 40\\\left(-\frac{k+2}{\left(k-4\right)\left(k+7\right)}\right)\times 20+\frac{3}{\left(k-4\right)\left(k+7\right)}\times 40\end{matrix}\right)$$

Mahia ngā tātaitanga.

$$\left(\begin{matrix}x\\y\end{matrix}\right)=\left(\begin{matrix}\frac{40}{k+7}\\-\frac{20}{k+7}\end{matrix}\right)$$

Tangohia ngā huānga poukapa x me y.

$$x=\frac{40}{k+7},y=-\frac{20}{k+7}$$

Ngā Upane e Whakamahi i te Tangohanga

Whakaarohia te whārite tuatahi. Whakamahia te āhuatanga tohatoha hei whakarea te k+1 ki te y.

$$3x-\left(ky+y\right)=20$$

Hei kimi i te tauaro o ky+y, kimihia te tauaro o ia taurangi.

$$3x-ky-y=20$$

Pahekotia ngā kīanga tau katoa e whai ana i te x,y.

$$3x+\left(-k-1\right)y=20$$

Whakaarohia te whārite tuarua. Whakamahia te āhuatanga tohatoha hei whakarea te k+2 ki te x.

$$kx+2x-10y=40$$

Pahekotia ngā kīanga tau katoa e whai ana i te x,y.

$$\left(k+2\right)x-10y=40$$

Hei whakaoti mā te tangohanga, ko ngā tau whakarea o tētahi o ngā taurangi me mātua ōrite i ngā whārite e rua kia whakakorehia ai te taurangi ina tangohia tētahi whārite mai i tētahi atu.

$$3x+\left(-k-1\right)y=20,\left(k+2\right)x-10y=40$$

Kia ōrite ai a 3x me \left(k+2\right)x, whakareatia ngā kīanga tau katoa kei ia taha o te whārite tuatahi ki te k+2 me ngā kīanga tau katoa kei ia taha o te whārite tuarua ki te 3.

$$\left(k+2\right)\times 3x+\left(k+2\right)\left(-k-1\right)y=\left(k+2\right)\times 20,3\left(k+2\right)x+3\left(-10\right)y=3\times 40$$

Whakarūnātia.

$$\left(3k+6\right)x+\left(-\left(k+1\right)\left(k+2\right)\right)y=20k+40,\left(3k+6\right)x-30y=120$$

Me tango \left(3k+6\right)x-30y=120 mai i \left(3k+6\right)x+\left(-\left(k+1\right)\left(k+2\right)\right)y=20k+40 mā te tango i ngā kīanga tau ōrite i ia taha o te tohu ōrite.

$$\left(3k+6\right)x+\left(-3k-6\right)x+\left(-\left(k+1\right)\left(k+2\right)\right)y+30y=20k+40-120$$

Tāpiri 3\left(2+k\right)x ki te -6x-3xk. Ka whakakore atu ngā kupu 3\left(2+k\right)x me -6x-3xk, ka toe he whārite me tētahi taurangi kotahi ka taea te whakaoti.

$$\left(-\left(k+1\right)\left(k+2\right)\right)y+30y=20k+40-120$$

Tāpiri -\left(k+2\right)\left(k+1\right)y ki te 30y.

$$\left(4-k\right)\left(k+7\right)y=20k+40-120$$

Tāpiri 20k+40 ki te -120.

$$\left(4-k\right)\left(k+7\right)y=20k-80$$

Whakawehea ngā taha e rua ki te \left(4-k\right)\left(7+k\right).

$$y=-\frac{20}{k+7}$$

Whakaurua te -\frac{20}{7+k} mō y ki \left(k+2\right)x-10y=40. I te mea kotahi anake te taurangi kei te whārite i puta, ka taea e koe te whakaoti mō x hāngai tonu.

$$\left(k+2\right)x-10\left(-\frac{20}{k+7}\right)=40$$

Whakareatia -10 ki te -\frac{20}{7+k}.

$$\left(k+2\right)x+\frac{200}{k+7}=40$$

Me tango \frac{200}{7+k} mai i ngā taha e rua o te whārite.

$$\left(k+2\right)x=\frac{40\left(k+2\right)}{k+7}$$

Whakawehea ngā taha e rua ki te k+2.

$$x=\frac{40}{k+7}$$

Kua oti te pūnaha te whakatau.

$$x=\frac{40}{k+7},y=-\frac{20}{k+7}$$