Whakaoti i te 3x^3-2x^2+5x-7-4x^2-3x+2

$$3 x ^ { 3 } - 2 x ^ { 2 } + 5 x - 7 - 4 x ^ { 2 } - 3 x + 2$$

Aromātai

$$3x^{3}-6x^{2}+2x-5$$

Ngā Upane Otinga

Pahekotia te -2x^{2} me -4x^{2}, ka -6x^{2}.

$$3x^{3}-6x^{2}+5x-7-3x+2$$

Pahekotia te 5x me -3x, ka 2x.

$$3x^{3}-6x^{2}+2x-7+2$$

Tāpirihia te -7 ki te 2, ka -5.

$$3x^{3}-6x^{2}+2x-5$$

Kimi Pārōnaki e ai ki x

$$9x^{2}-12x+2$$

Ngā Upane e Whakamahi ana i te Ture Pārōnaki mō te Tapeke

Pahekotia te -2x^{2} me -4x^{2}, ka -6x^{2}.

$$\frac{\mathrm{d}}{\mathrm{d}x}(3x^{3}-6x^{2}+5x-7-3x+2)$$

Pahekotia te 5x me -3x, ka 2x.

$$\frac{\mathrm{d}}{\mathrm{d}x}(3x^{3}-6x^{2}+2x-7+2)$$

Tāpirihia te -7 ki te 2, ka -5.

$$\frac{\mathrm{d}}{\mathrm{d}x}(3x^{3}-6x^{2}+2x-5)$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$3\times 3x^{3-1}+2\left(-6\right)x^{2-1}+2x^{1-1}$$

Whakareatia 3 ki te 3.

$$9x^{3-1}+2\left(-6\right)x^{2-1}+2x^{1-1}$$

Tango 1 mai i 3.

$$9x^{2}+2\left(-6\right)x^{2-1}+2x^{1-1}$$

Whakareatia 2 ki te -6.

$$9x^{2}-12x^{2-1}+2x^{1-1}$$

Tango 1 mai i 2.

$$9x^{2}-12x^{1}+2x^{1-1}$$

Tango 1 mai i 1.

$$9x^{2}-12x^{1}+2x^{0}$$

Mō tētahi kupu t, t^{1}=t.

$$9x^{2}-12x+2x^{0}$$

Mō tētahi kupu t mahue te 0, t^{0}=1.

$$9x^{2}-12x+2\times 1$$

Mō tētahi kupu t, t\times 1=t me 1t=t.

$$9x^{2}-12x+2$$