Whakaoti i te 3x^2-xgeqx^2-5x

$$3 x ^ { 2 } - x \geq x ^ { 2 } - 5 x$$

Whakaoti mō x

$$x\in (-\infty,-2]\cup [0,\infty)$$

Ngā Upane Otinga

Tangohia te x^{2} mai i ngā taha e rua.

$$3x^{2}-x-x^{2}\geq -5x$$

Pahekotia te 3x^{2} me -x^{2}, ka 2x^{2}.

$$2x^{2}-x\geq -5x$$

Me tāpiri te 5x ki ngā taha e rua.

$$2x^{2}-x+5x\geq 0$$

Pahekotia te -x me 5x, ka 4x.

$$2x^{2}+4x\geq 0$$

Tauwehea te x.

$$2x\left(x+2\right)\geq 0$$

Kia ≥0 te otinga, me ≤0 tahi, me ≥0 tahi rānei te x+2 me te x. Whakaarohia te tauira ina he ≤0 tahi te x+2 me te x.

$$x+2\leq 0 x\leq 0$$

Te otinga e whakaea i ngā koreōrite e rua ko x\leq -2.

$$x\leq -2$$

Whakaarohia te tauira ina he ≥0 tahi te x+2 me te x.

$$x\geq 0 x+2\geq 0$$

Te otinga e whakaea i ngā koreōrite e rua ko x\geq 0.

$$x\geq 0$$

Ko te otinga whakamutunga ko te whakakotahi i ngā otinga kua whiwhi.

$$x\leq -2\text{; }x\geq 0$$