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Tauwehe
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x\left(3x-5\right)
Tauwehea te x.
3x^{2}-5x=0
Ka taea te huamaha pūrua te tauwehe mā te whakamahi i te huringa ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), ina ko x_{1} me x_{2} ngā otinga o te whārite pūrua ax^{2}+bx+c=0.
x=\frac{-\left(-5\right)±\sqrt{\left(-5\right)^{2}}}{2\times 3}
Ko ngā whārite katoa o te āhua ax^{2}+bx+c=0 ka taea te whakaoti mā te whakamahi i te tikanga tātai pūrua: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. E rua ngā otinga ka puta i te tikanga tātai pūrua, ko tētahi ina he tāpiri a ±, ā, ko tētahi ina he tango.
x=\frac{-\left(-5\right)±5}{2\times 3}
Tuhia te pūtakerua o te \left(-5\right)^{2}.
x=\frac{5±5}{2\times 3}
Ko te tauaro o -5 ko 5.
x=\frac{5±5}{6}
Whakareatia 2 ki te 3.
x=\frac{10}{6}
Nā, me whakaoti te whārite x=\frac{5±5}{6} ina he tāpiri te ±. Tāpiri 5 ki te 5.
x=\frac{5}{3}
Whakahekea te hautanga \frac{10}{6} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 2.
x=\frac{0}{6}
Nā, me whakaoti te whārite x=\frac{5±5}{6} ina he tango te ±. Tango 5 mai i 5.
x=0
Whakawehe 0 ki te 6.
3x^{2}-5x=3\left(x-\frac{5}{3}\right)x
Tauwehea te kīanga taketake mā te whakamahi i te ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Me whakakapi te \frac{5}{3} mō te x_{1} me te 0 mō te x_{2}.
3x^{2}-5x=3\times \frac{3x-5}{3}x
Tango \frac{5}{3} mai i x mā te kimi i te tauraro pātahi me te tango i ngā taurunga, ka whakaiti i te hautanga ki ngā kīanga tau iti rawa e taea ana.
3x^{2}-5x=\left(3x-5\right)x
Whakakorea atu te tauwehe pūnoa nui rawa 3 i roto i te 3 me te 3.