Whakaoti i te 3x^2=75

$$3 x ^ { 2 } = 75$$

Whakaoti mō x

$$x=5$$

$$x=-5$$

Ngā Hipanga Whakamahi Rerekētanga o ngā Pūrua

Whakawehea ngā taha e rua ki te 3.

$$x^{2}=\frac{75}{3}$$

Whakawehea te 75 ki te 3, kia riro ko 25.

$$x^{2}=25$$

Tangohia te 25 mai i ngā taha e rua.

$$x^{2}-25=0$$

Whakaarohia te x^{2}-25. Tuhia anō te x^{2}-25 hei x^{2}-5^{2}. Ka taea te rerekētanga o ngā pūrua te whakatauwehe mā te ture: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).

$$\left(x-5\right)\left(x+5\right)=0$$

Hei kimi otinga whārite, me whakaoti te x-5=0 me te x+5=0.

$$x=5 x=-5$$

Ngā Upane mā te Kimi Pūtakerua

Whakawehea ngā taha e rua ki te 3.

$$x^{2}=\frac{75}{3}$$

Whakawehea te 75 ki te 3, kia riro ko 25.

$$x^{2}=25$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$x=5 x=-5$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Whakawehea ngā taha e rua ki te 3.

$$x^{2}=\frac{75}{3}$$

Whakawehea te 75 ki te 3, kia riro ko 25.

$$x^{2}=25$$

Tangohia te 25 mai i ngā taha e rua.

$$x^{2}-25=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me -25 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-25\right)}}{2}$$

Pūrua 0.

$$x=\frac{0±\sqrt{-4\left(-25\right)}}{2}$$

Whakareatia -4 ki te -25.

$$x=\frac{0±\sqrt{100}}{2}$$

Tuhia te pūtakerua o te 100.

$$x=\frac{0±10}{2}$$

Nā, me whakaoti te whārite x=\frac{0±10}{2} ina he tāpiri te ±. Whakawehe 10 ki te 2.

$$x=5$$

Nā, me whakaoti te whārite x=\frac{0±10}{2} ina he tango te ±. Whakawehe -10 ki te 2.

$$x=-5$$

Kua oti te whārite te whakatau.

$$x=5 x=-5$$