Whakaoti i te 3x^2=15

$$3 x ^ { 2 } = 15$$

Whakaoti mō x

$$x=\sqrt{5}\approx 2.236067977$$

$$x=-\sqrt{5}\approx -2.236067977$$

Ngā Upane mā te Kimi Pūtakerua

Whakawehea ngā taha e rua ki te 3.

$$x^{2}=\frac{15}{3}$$

Whakawehea te 15 ki te 3, kia riro ko 5.

$$x^{2}=5$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$x=\sqrt{5} x=-\sqrt{5}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Whakawehea ngā taha e rua ki te 3.

$$x^{2}=\frac{15}{3}$$

Whakawehea te 15 ki te 3, kia riro ko 5.

$$x^{2}=5$$

Tangohia te 5 mai i ngā taha e rua.

$$x^{2}-5=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me -5 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-5\right)}}{2}$$

Pūrua 0.

$$x=\frac{0±\sqrt{-4\left(-5\right)}}{2}$$

Whakareatia -4 ki te -5.

$$x=\frac{0±\sqrt{20}}{2}$$

Tuhia te pūtakerua o te 20.

$$x=\frac{0±2\sqrt{5}}{2}$$

Nā, me whakaoti te whārite x=\frac{0±2\sqrt{5}}{2} ina he tāpiri te ±.

$$x=\sqrt{5}$$

Nā, me whakaoti te whārite x=\frac{0±2\sqrt{5}}{2} ina he tango te ±.

$$x=-\sqrt{5}$$

Kua oti te whārite te whakatau.

$$x=\sqrt{5} x=-\sqrt{5}$$