Whakaoti i te 3x^2+5=8

$$3 x ^ { 2 } + 5 = 8$$

Whakaoti mō x

$$x=1$$

$$x=-1$$

Ngā Hipanga Whakamahi Rerekētanga o ngā Pūrua

Tangohia te 8 mai i ngā taha e rua.

$$3x^{2}+5-8=0$$

Tangohia te 8 i te 5, ka -3.

$$3x^{2}-3=0$$

Whakawehea ngā taha e rua ki te 3.

$$x^{2}-1=0$$

Whakaarohia te x^{2}-1. Tuhia anō te x^{2}-1 hei x^{2}-1^{2}. Ka taea te rerekētanga o ngā pūrua te whakatauwehe mā te ture: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).

$$\left(x-1\right)\left(x+1\right)=0$$

Hei kimi otinga whārite, me whakaoti te x-1=0 me te x+1=0.

$$x=1 x=-1$$

Ngā Upane mā te Kimi Pūtakerua

Tangohia te 5 mai i ngā taha e rua.

$$3x^{2}=8-5$$

Tangohia te 5 i te 8, ka 3.

$$3x^{2}=3$$

Whakawehea ngā taha e rua ki te 3.

$$x^{2}=\frac{3}{3}$$

Whakawehea te 3 ki te 3, kia riro ko 1.

$$x^{2}=1$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$x=1 x=-1$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Tangohia te 8 mai i ngā taha e rua.

$$3x^{2}+5-8=0$$

Tangohia te 8 i te 5, ka -3.

$$3x^{2}-3=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 3 mō a, 0 mō b, me -3 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\times 3\left(-3\right)}}{2\times 3}$$

Pūrua 0.

$$x=\frac{0±\sqrt{-4\times 3\left(-3\right)}}{2\times 3}$$

Whakareatia -4 ki te 3.

$$x=\frac{0±\sqrt{-12\left(-3\right)}}{2\times 3}$$

Whakareatia -12 ki te -3.

$$x=\frac{0±\sqrt{36}}{2\times 3}$$

Tuhia te pūtakerua o te 36.

$$x=\frac{0±6}{2\times 3}$$

Whakareatia 2 ki te 3.

$$x=\frac{0±6}{6}$$

Nā, me whakaoti te whārite x=\frac{0±6}{6} ina he tāpiri te ±. Whakawehe 6 ki te 6.

$$x=1$$

Nā, me whakaoti te whārite x=\frac{0±6}{6} ina he tango te ±. Whakawehe -6 ki te 6.

$$x=-1$$

Kua oti te whārite te whakatau.

$$x=1 x=-1$$