Whakaoti i te 3x^2+5=10

$$3 x ^ { 2 } + 5 = 10$$

Whakaoti mō x

$$x = \frac{\sqrt{15}}{3} \approx 1.290994449$$

$$x = -\frac{\sqrt{15}}{3} \approx -1.290994449$$

Ngā Upane mā te Kimi Pūtakerua

Tangohia te 5 mai i ngā taha e rua.

$$3x^{2}=10-5$$

Tangohia te 5 i te 10, ka 5.

$$3x^{2}=5$$

Whakawehea ngā taha e rua ki te 3.

$$x^{2}=\frac{5}{3}$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$x=\frac{\sqrt{15}}{3} x=-\frac{\sqrt{15}}{3}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Tangohia te 10 mai i ngā taha e rua.

$$3x^{2}+5-10=0$$

Tangohia te 10 i te 5, ka -5.

$$3x^{2}-5=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 3 mō a, 0 mō b, me -5 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\times 3\left(-5\right)}}{2\times 3}$$

Pūrua 0.

$$x=\frac{0±\sqrt{-4\times 3\left(-5\right)}}{2\times 3}$$

Whakareatia -4 ki te 3.

$$x=\frac{0±\sqrt{-12\left(-5\right)}}{2\times 3}$$

Whakareatia -12 ki te -5.

$$x=\frac{0±\sqrt{60}}{2\times 3}$$

Tuhia te pūtakerua o te 60.

$$x=\frac{0±2\sqrt{15}}{2\times 3}$$

Whakareatia 2 ki te 3.

$$x=\frac{0±2\sqrt{15}}{6}$$

Nā, me whakaoti te whārite x=\frac{0±2\sqrt{15}}{6} ina he tāpiri te ±.

$$x=\frac{\sqrt{15}}{3}$$

Nā, me whakaoti te whārite x=\frac{0±2\sqrt{15}}{6} ina he tango te ±.

$$x=-\frac{\sqrt{15}}{3}$$

Kua oti te whārite te whakatau.

$$x=\frac{\sqrt{15}}{3} x=-\frac{\sqrt{15}}{3}$$