Whakaoti i te 3x^2+2=25

$$3 x ^ { 2 } + 2 = 25$$

Whakaoti mō x

$$x = \frac{\sqrt{69}}{3} \approx 2.768874621$$

$$x = -\frac{\sqrt{69}}{3} \approx -2.768874621$$

Ngā Upane mā te Kimi Pūtakerua

Tangohia te 2 mai i ngā taha e rua.

$$3x^{2}=25-2$$

Tangohia te 2 i te 25, ka 23.

$$3x^{2}=23$$

Whakawehea ngā taha e rua ki te 3.

$$x^{2}=\frac{23}{3}$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$x=\frac{\sqrt{69}}{3} x=-\frac{\sqrt{69}}{3}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Tangohia te 25 mai i ngā taha e rua.

$$3x^{2}+2-25=0$$

Tangohia te 25 i te 2, ka -23.

$$3x^{2}-23=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 3 mō a, 0 mō b, me -23 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\times 3\left(-23\right)}}{2\times 3}$$

Pūrua 0.

$$x=\frac{0±\sqrt{-4\times 3\left(-23\right)}}{2\times 3}$$

Whakareatia -4 ki te 3.

$$x=\frac{0±\sqrt{-12\left(-23\right)}}{2\times 3}$$

Whakareatia -12 ki te -23.

$$x=\frac{0±\sqrt{276}}{2\times 3}$$

Tuhia te pūtakerua o te 276.

$$x=\frac{0±2\sqrt{69}}{2\times 3}$$

Whakareatia 2 ki te 3.

$$x=\frac{0±2\sqrt{69}}{6}$$

Nā, me whakaoti te whārite x=\frac{0±2\sqrt{69}}{6} ina he tāpiri te ±.

$$x=\frac{\sqrt{69}}{3}$$

Nā, me whakaoti te whārite x=\frac{0±2\sqrt{69}}{6} ina he tango te ±.

$$x=-\frac{\sqrt{69}}{3}$$

Kua oti te whārite te whakatau.

$$x=\frac{\sqrt{69}}{3} x=-\frac{\sqrt{69}}{3}$$