Whakaoti i te 3x^2+1=5

$$3 x ^ { 2 } + 1 = 5$$

Whakaoti mō x

$$x = \frac{2 \sqrt{3}}{3} \approx 1.154700538$$

$$x = -\frac{2 \sqrt{3}}{3} \approx -1.154700538$$

Ngā Upane mā te Kimi Pūtakerua

Tangohia te 1 mai i ngā taha e rua.

$$3x^{2}=5-1$$

Tangohia te 1 i te 5, ka 4.

$$3x^{2}=4$$

Whakawehea ngā taha e rua ki te 3.

$$x^{2}=\frac{4}{3}$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$x=\frac{2\sqrt{3}}{3} x=-\frac{2\sqrt{3}}{3}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Tangohia te 5 mai i ngā taha e rua.

$$3x^{2}+1-5=0$$

Tangohia te 5 i te 1, ka -4.

$$3x^{2}-4=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 3 mō a, 0 mō b, me -4 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\times 3\left(-4\right)}}{2\times 3}$$

Pūrua 0.

$$x=\frac{0±\sqrt{-4\times 3\left(-4\right)}}{2\times 3}$$

Whakareatia -4 ki te 3.

$$x=\frac{0±\sqrt{-12\left(-4\right)}}{2\times 3}$$

Whakareatia -12 ki te -4.

$$x=\frac{0±\sqrt{48}}{2\times 3}$$

Tuhia te pūtakerua o te 48.

$$x=\frac{0±4\sqrt{3}}{2\times 3}$$

Whakareatia 2 ki te 3.

$$x=\frac{0±4\sqrt{3}}{6}$$

Nā, me whakaoti te whārite x=\frac{0±4\sqrt{3}}{6} ina he tāpiri te ±.

$$x=\frac{2\sqrt{3}}{3}$$

Nā, me whakaoti te whārite x=\frac{0±4\sqrt{3}}{6} ina he tango te ±.

$$x=-\frac{2\sqrt{3}}{3}$$

Kua oti te whārite te whakatau.

$$x=\frac{2\sqrt{3}}{3} x=-\frac{2\sqrt{3}}{3}$$