Whakaoti i te 3x^2+1=2x+7

$$3 x ^ { 2 } + 1 = 2 x + 7$$

Whakaoti mō x

$$x = \frac{\sqrt{19} + 1}{3} \approx 1.786299648$$

$$x=\frac{1-\sqrt{19}}{3}\approx -1.119632981$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Tangohia te 2x mai i ngā taha e rua.

$$3x^{2}+1-2x=7$$

Tangohia te 7 mai i ngā taha e rua.

$$3x^{2}+1-2x-7=0$$

Tangohia te 7 i te 1, ka -6.

$$3x^{2}-6-2x=0$$

Ko ngā whārite katoa o te āhua ax^{2}+bx+c=0 ka taea te whakaoti mā te whakamahi i te tikanga tātai pūrua: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. E rua ngā otinga ka puta i te tikanga tātai pūrua, ko tētahi ina he tāpiri a ±, ā, ko tētahi ina he tango.

$$3x^{2}-2x-6=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 3 mō a, -2 mō b, me -6 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{-\left(-2\right)±\sqrt{\left(-2\right)^{2}-4\times 3\left(-6\right)}}{2\times 3}$$

Pūrua -2.

$$x=\frac{-\left(-2\right)±\sqrt{4-4\times 3\left(-6\right)}}{2\times 3}$$

Whakareatia -4 ki te 3.

$$x=\frac{-\left(-2\right)±\sqrt{4-12\left(-6\right)}}{2\times 3}$$

Whakareatia -12 ki te -6.

$$x=\frac{-\left(-2\right)±\sqrt{4+72}}{2\times 3}$$

Tāpiri 4 ki te 72.

$$x=\frac{-\left(-2\right)±\sqrt{76}}{2\times 3}$$

Tuhia te pūtakerua o te 76.

$$x=\frac{-\left(-2\right)±2\sqrt{19}}{2\times 3}$$

Ko te tauaro o -2 ko 2.

$$x=\frac{2±2\sqrt{19}}{2\times 3}$$

Whakareatia 2 ki te 3.

$$x=\frac{2±2\sqrt{19}}{6}$$

Nā, me whakaoti te whārite x=\frac{2±2\sqrt{19}}{6} ina he tāpiri te ±. Tāpiri 2 ki te 2\sqrt{19}.

$$x=\frac{2\sqrt{19}+2}{6}$$

Whakawehe 2+2\sqrt{19} ki te 6.

$$x=\frac{\sqrt{19}+1}{3}$$

Nā, me whakaoti te whārite x=\frac{2±2\sqrt{19}}{6} ina he tango te ±. Tango 2\sqrt{19} mai i 2.

$$x=\frac{2-2\sqrt{19}}{6}$$

Whakawehe 2-2\sqrt{19} ki te 6.

$$x=\frac{1-\sqrt{19}}{3}$$

Kua oti te whārite te whakatau.

$$x=\frac{\sqrt{19}+1}{3} x=\frac{1-\sqrt{19}}{3}$$

Ngā Upane mō te Whakaoti i te Pūrua

Tangohia te 2x mai i ngā taha e rua.

$$3x^{2}+1-2x=7$$

Tangohia te 1 mai i ngā taha e rua.

$$3x^{2}-2x=7-1$$

Tangohia te 1 i te 7, ka 6.

$$3x^{2}-2x=6$$

Whakawehea ngā taha e rua ki te 3.

$$\frac{3x^{2}-2x}{3}=\frac{6}{3}$$

Mā te whakawehe ki te 3 ka wetekia te whakareanga ki te 3.

$$x^{2}-\frac{2}{3}x=\frac{6}{3}$$

Whakawehe 6 ki te 3.

$$x^{2}-\frac{2}{3}x=2$$

Whakawehea te -\frac{2}{3}, te tau whakarea o te kīanga tau x, ki te 2 kia riro ai te -\frac{1}{3}. Nā, tāpiria te pūrua o te -\frac{1}{3} ki ngā taha e rua o te whārite. Mā konei e pūrua tika tonu ai te taha mauī o te whārite.

$$x^{2}-\frac{2}{3}x+\left(-\frac{1}{3}\right)^{2}=2+\left(-\frac{1}{3}\right)^{2}$$

Pūruatia -\frac{1}{3} mā te pūrua i te taurunga me te tauraro o te hautanga.

$$x^{2}-\frac{2}{3}x+\frac{1}{9}=2+\frac{1}{9}$$

Tāpiri 2 ki te \frac{1}{9}.

$$x^{2}-\frac{2}{3}x+\frac{1}{9}=\frac{19}{9}$$

Tauwehea x^{2}-\frac{2}{3}x+\frac{1}{9}. Ko te tikanga pūnoa, ina ko x^{2}+bx+c he pūrua tika pūrua tika pū, ka taea taua mea te tauwehea i ngā wā katoa hei \left(x+\frac{b}{2}\right)^{2}.

$$\left(x-\frac{1}{3}\right)^{2}=\frac{19}{9}$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$\sqrt{\left(x-\frac{1}{3}\right)^{2}}=\sqrt{\frac{19}{9}}$$

Whakarūnātia.

$$x-\frac{1}{3}=\frac{\sqrt{19}}{3} x-\frac{1}{3}=-\frac{\sqrt{19}}{3}$$

Me tāpiri \frac{1}{3} ki ngā taha e rua o te whārite.

$$x=\frac{\sqrt{19}+1}{3} x=\frac{1-\sqrt{19}}{3}$$