Whakaoti i te 3t^2=38*5

$$3 t ^ { 2 } = 38 \times 5$$

Whakaoti mō t

$$t = \frac{\sqrt{570}}{3} \approx 7.958224258$$

$$t = -\frac{\sqrt{570}}{3} \approx -7.958224258$$

Ngā Upane mā te Kimi Pūtakerua

Whakareatia te 38 ki te 5, ka 190.

$$3t^{2}=190$$

Whakawehea ngā taha e rua ki te 3.

$$t^{2}=\frac{190}{3}$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$t=\frac{\sqrt{570}}{3} t=-\frac{\sqrt{570}}{3}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Whakareatia te 38 ki te 5, ka 190.

$$3t^{2}=190$$

Tangohia te 190 mai i ngā taha e rua.

$$3t^{2}-190=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 3 mō a, 0 mō b, me -190 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$t=\frac{0±\sqrt{0^{2}-4\times 3\left(-190\right)}}{2\times 3}$$

Pūrua 0.

$$t=\frac{0±\sqrt{-4\times 3\left(-190\right)}}{2\times 3}$$

Whakareatia -4 ki te 3.

$$t=\frac{0±\sqrt{-12\left(-190\right)}}{2\times 3}$$

Whakareatia -12 ki te -190.

$$t=\frac{0±\sqrt{2280}}{2\times 3}$$

Tuhia te pūtakerua o te 2280.

$$t=\frac{0±2\sqrt{570}}{2\times 3}$$

Whakareatia 2 ki te 3.

$$t=\frac{0±2\sqrt{570}}{6}$$

Nā, me whakaoti te whārite t=\frac{0±2\sqrt{570}}{6} ina he tāpiri te ±.

$$t=\frac{\sqrt{570}}{3}$$

Nā, me whakaoti te whārite t=\frac{0±2\sqrt{570}}{6} ina he tango te ±.

$$t=-\frac{\sqrt{570}}{3}$$

Kua oti te whārite te whakatau.

$$t=\frac{\sqrt{570}}{3} t=-\frac{\sqrt{570}}{3}$$