Whakaoti i te 3n^2=7+4

$$3 n ^ { 2 } = 7 + 4$$

Whakaoti mō n

$$n = \frac{\sqrt{33}}{3} \approx 1.914854216$$

$$n = -\frac{\sqrt{33}}{3} \approx -1.914854216$$

Ngā Upane mā te Kimi Pūtakerua

Tāpirihia te 7 ki te 4, ka 11.

$$3n^{2}=11$$

Whakawehea ngā taha e rua ki te 3.

$$n^{2}=\frac{11}{3}$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$n=\frac{\sqrt{33}}{3} n=-\frac{\sqrt{33}}{3}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Tāpirihia te 7 ki te 4, ka 11.

$$3n^{2}=11$$

Tangohia te 11 mai i ngā taha e rua.

$$3n^{2}-11=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 3 mō a, 0 mō b, me -11 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$n=\frac{0±\sqrt{0^{2}-4\times 3\left(-11\right)}}{2\times 3}$$

Pūrua 0.

$$n=\frac{0±\sqrt{-4\times 3\left(-11\right)}}{2\times 3}$$

Whakareatia -4 ki te 3.

$$n=\frac{0±\sqrt{-12\left(-11\right)}}{2\times 3}$$

Whakareatia -12 ki te -11.

$$n=\frac{0±\sqrt{132}}{2\times 3}$$

Tuhia te pūtakerua o te 132.

$$n=\frac{0±2\sqrt{33}}{2\times 3}$$

Whakareatia 2 ki te 3.

$$n=\frac{0±2\sqrt{33}}{6}$$

Nā, me whakaoti te whārite n=\frac{0±2\sqrt{33}}{6} ina he tāpiri te ±.

$$n=\frac{\sqrt{33}}{3}$$

Nā, me whakaoti te whārite n=\frac{0±2\sqrt{33}}{6} ina he tango te ±.

$$n=-\frac{\sqrt{33}}{3}$$

Kua oti te whārite te whakatau.

$$n=\frac{\sqrt{33}}{3} n=-\frac{\sqrt{33}}{3}$$