Whakaoti i te 3-m^2=-7

$$3 - m ^ { 2 } = - 7$$

Whakaoti mō m

$$m=\sqrt{10}\approx 3.16227766$$

$$m=-\sqrt{10}\approx -3.16227766$$

Ngā Upane mā te Kimi Pūtakerua

Tangohia te 3 mai i ngā taha e rua.

$$-m^{2}=-7-3$$

Tangohia te 3 i te -7, ka -10.

$$-m^{2}=-10$$

Whakawehea ngā taha e rua ki te -1.

$$m^{2}=\frac{-10}{-1}$$

Ka taea te hautanga \frac{-10}{-1} te whakamāmā ki te 10 mā te tango tahi i te tohu tōraro i te taurunga me te tauraro.

$$m^{2}=10$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$m=\sqrt{10} m=-\sqrt{10}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Me tāpiri te 7 ki ngā taha e rua.

$$3-m^{2}+7=0$$

Tāpirihia te 3 ki te 7, ka 10.

$$10-m^{2}=0$$

Ko ngā tikanga tātai pūrua pēnei i tēnei nā, me te kīanga tau x^{2} engari kāore he kīanga tau x, ka taea tonu te whakaoti mā te whakamahi i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, ina tuhia ki te tānga ngahuru: ax^{2}+bx+c=0.

$$-m^{2}+10=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi -1 mō a, 0 mō b, me 10 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$m=\frac{0±\sqrt{0^{2}-4\left(-1\right)\times 10}}{2\left(-1\right)}$$

Pūrua 0.

$$m=\frac{0±\sqrt{-4\left(-1\right)\times 10}}{2\left(-1\right)}$$

Whakareatia -4 ki te -1.

$$m=\frac{0±\sqrt{4\times 10}}{2\left(-1\right)}$$

Whakareatia 4 ki te 10.

$$m=\frac{0±\sqrt{40}}{2\left(-1\right)}$$

Tuhia te pūtakerua o te 40.

$$m=\frac{0±2\sqrt{10}}{2\left(-1\right)}$$

Whakareatia 2 ki te -1.

$$m=\frac{0±2\sqrt{10}}{-2}$$

Nā, me whakaoti te whārite m=\frac{0±2\sqrt{10}}{-2} ina he tāpiri te ±.

$$m=-\sqrt{10}$$

Nā, me whakaoti te whārite m=\frac{0±2\sqrt{10}}{-2} ina he tango te ±.

$$m=\sqrt{10}$$

Kua oti te whārite te whakatau.

$$m=-\sqrt{10} m=\sqrt{10}$$